What is the remainder of f(x^7) when divided by f(x)?
f(x) =1+x+x^2+x^3+...+x^7

• the ans is 7
• 8 years agoHelpfull: Yes(4) No(4)
• a/c to me ans will be 0
  f(x)=1+x+x^2+...+x^7
  f(x^7)=1+x^7+x^14+x^21+....x^49
  f(x^7)=1+x^7(1+x^2+x^3+...x^7)
  f(x^7)/f(x)=1+x^7(1+x+x^2+x^3+..+x^7-x)/f(x)
  f(x^7)/f(x)=[1+x^7(f(x)-x)]/f(x)
  =1+x^8 it can be represented as
  (1-x)(1+x+x^2++...+x^7) which is divisible by f(x)
  so rem=0
  
  
• 8 years agoHelpfull: Yes(2) No(4)
• ans must be 7
• 8 years agoHelpfull: Yes(1) No(0)
• can any 1 explain it clearly??????????
• 8 years agoHelpfull: Yes(1) No(0)
• f(x)= 1+x+x^2+x^3+....+x^7
  f(x^7) = 1+x^7+x^14+x^21+.....+x^49
  Now. to get the remainder we can write above equations as :
  Remainder = f(x^7) - x^7*f(x) = 1 - x^8
• 8 years agoHelpfull: Yes(0) No(5)