123
12345
1234567
123456789
print this pattern upto 10 terms..

• #include
  main()
  {
  int i,j,n;
  printf("enter the no od lines u want");
  scanf("%d",&n);
  for(i=1;i
• 8 years agoHelpfull: Yes(36) No(17)
• #include
  int main()
  {
  int i,j,k;
  printf("Enter the odd number upto which you want to print the pattern:");
  scanf("%d",&k);
  for(i=1;i
• 8 years agoHelpfull: Yes(13) No(5)
• //In Java
  class Pattern
  {
  PSVM()
  {
  for(int i=3;i
• 8 years agoHelpfull: Yes(6) No(2)
• #include
  int main()
  {
  int i,j;
  for (i = 1 ; i
• 8 years agoHelpfull: Yes(4) No(4)
• int j=3;
  for(I=1;i=10)
  break;
  }
  }
  
• 8 years agoHelpfull: Yes(2) No(1)
• The perfect solution for this is ,
  
  123
  12345
  1234567
  here from 123 to 12345 ,2 values are increasing and each row
  row 0=10-7 3 nos are printed
  row 1=10-5 (10-7-2)
  row 3=10-3 (10-7-2*2)
  so on till 10 terms 10-(7*2*i)
  int main()
  {
  int i,j,n=10;
  for(i=0;i
• 7 years agoHelpfull: Yes(2) No(4)
• the above expained only logic bt didnt expain the program
  int main()
  {
  int i,j,n=10;
  for(i=0;i
• 7 years agoHelpfull: Yes(1) No(1)
• #include
  main()
  {
  int i,j,n=10;
  for(i=3;i
• 5 years agoHelpfull: Yes(1) No(0)
• what is the correct answer????
• 8 years agoHelpfull: Yes(0) No(0)
• for(i=1;i
• 8 years agoHelpfull: Yes(0) No(0)
• #include
  void main()
  {
  int i,j,k=0;
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(2)
• for(int i=1;i
• 8 years agoHelpfull: Yes(0) No(1)
• #include
  main()
  {
  int i,j,n=4;
  for(i=1;i
• 8 years agoHelpfull: Yes(0) No(2)
• for(i=1;i
• 8 years agoHelpfull: Yes(0) No(2)
• #include
  void main()
  {
  for(int i=3;i
• 7 years agoHelpfull: Yes(0) No(1)
• int x=3;
  for(int i=1;i
• 7 years agoHelpfull: Yes(0) No(1)
• void printPattern()
  {
  int i,j,count;
  for(i=1;i
• 7 years agoHelpfull: Yes(0) No(0)
• class check
  {
  public static void main(String args[])
  {
  long i=123,j,a,b,c,x;
  for(a=1;a
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  void main()
  {
  int i,j;
  for(i=1;i
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int n,i,j,s;
  printf("n:");
  scanf("%d",&n);
  s=0;
  for(i=1;i
• 6 years agoHelpfull: Yes(0) No(0)
• for(i=2; i
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  
  int main()
  {
  int i,j,k;
  for(k=1;k
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int i;
  int j=3;
  while(j
• 6 years agoHelpfull: Yes(0) No(1)
• /* This code is adopted from the solution given
  @ http://effprog.blogspot.com/2011/01/spiral-printing-of-two-dimensional.html */
  
  #include
  #define R 3
  #define C 6
  
  int main()
  {int n=3;
  for(int i=1;i
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  int main(){
  int n;
  scanf("%d",&n);
  int, i,count=3;
  while(count
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  #include
  int main(int arg,char *args[])
  {
  int i,j;
  for(i=1;i
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  
  int main(int argc, char*argv[])
  {
  int i,j,n;
  n=atoi(argv[1]);
  for(i=1;i
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int i,j,n;
  scanf("%d",&n);
  for(i=3;i
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  #include
  int main(int argc,char *argv[])
  {
  int a,b,c,d,e,f,count=1,temp=3;
  a=atoi(argv[1]);
  for(b=0;b
• 6 years agoHelpfull: Yes(0) No(0)
• #include
  void main()
  {
  int i,j,;
  clrscr();
  for(i=1;i
• 5 years agoHelpfull: Yes(0) No(0)
• class Pattt
  {
  public static void main(String args[])
  {
  for(int i=3;i
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  void main()
  {
  int i,j;
  for(i=3;i
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  int main()
  {
  int i,j;
  for(i=3;i
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  #include
  void main(){int i,j;clrscr();for(i=1;i
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  void main()
  {
  int i,j,a,n=5;
  for(i=1;i
• 5 years agoHelpfull: Yes(0) No(0)
• #include
  void main()
  {
  int i,j;
  for( i=3;i
• 4 years agoHelpfull: Yes(0) No(0)
• this is the logic for printing the required pattern where n is required number of rows
  int printPat(int n)
  {
  int i,j;
  for(i=1;i
• 4 years agoHelpfull: Yes(0) No(0)
• #include
  
  int main()
  {
  int i,j,n=3;
  for(i=1;i
• 4 years agoHelpfull: Yes(0) No(0)
• void main()
  {
  int n,l=3,i,j;
  scanf("%d",&n);
  for(i=0;i
• 3 years agoHelpfull: Yes(0) No(0)