3 houses are available in a locality.
3 persons apply for the houses.Each apply for one house without consulting others.the probablity that all 3 apply for the same house is:
a)2/9
b)1/9
c)8/9
d)7/9

• let there be three house a,b,c then there would be 27 ways in which 3 person x,y,z select house
  there will be 1 case when x,y,z will buy house a
  another when they buy house b
  and another when they buy house c
  so the prob that they buy same house is 3*1/27=1/9
  Ans) (b) 1/9
• 9 years agoHelpfull: Yes(29) No(1)
• 7/9
  find the probabilty when people apply for different houses.
• 9 years agoHelpfull: Yes(2) No(4)
• 1/3*1/3*1/3
• 9 years agoHelpfull: Yes(2) No(8)
• let there be three house a,b,c then there would be 27 ways in which 3 person x,y,z select house
  there will be 1 case when x,y,z will buy house a
  another when they buy house b
  and another when they buy house c
  so the prob that they buy same house is 3*1/27=1/9
  
• 9 years agoHelpfull: Yes(2) No(1)
• 1/9 is ans
• 9 years agoHelpfull: Yes(1) No(1)
• 1/9 IS ANSWER
• 9 years agoHelpfull: Yes(1) No(0)
• probability of selecting any one is 1/3
  and selecting one from three is 1/9
• 9 years agoHelpfull: Yes(1) No(0)
• Ans = b;
  For a particular house being selected, probability = 1/3
  Probability all the persons apply for the same house = (1/3×1/3×1/3)3
  =(1/27)×3
  =1/9
  =19
• 6 years agoHelpfull: Yes(1) No(0)
• One person can select one house out of 3= inline {color{Black}3C_{1}} ways =3.
  Hence, three persons can select one house out of 3 in 3 x 3 x 3 =9.
  Therefore, probability that all thre apply for the same house is 1/9
• 9 years agoHelpfull: Yes(0) No(0)
• 3/3*1/3*1/3 = 1/9
• 9 years agoHelpfull: Yes(0) No(0)
• Let 1 person select 1 house. Then the probability that 2nd and 3rd also apply for the same house is 1/3 X 1/3 as total houses are 3.
  
  = 1/9
• 7 years agoHelpfull: Yes(0) No(0)