In a rectangular coordinate system, what is the area of a triangle whose vertices have the coordinates (4, 0), (6, 3), and (6, -3)?

• 1/2*6*2=6
  Ans=6
• 8 years agoHelpfull: Yes(6) No(0)
• are of triabgle with coordinates= (x1,y1) (x2,y2) (x3,y3) is = [x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]/2
  using this formula area = 6
• 8 years agoHelpfull: Yes(4) No(2)
• 1/2 * 6 * 4= 12...
  b=6.... h=4
• 8 years agoHelpfull: Yes(2) No(1)
• here first try to draw the fig.. i know its a bit time consuming butit will give u the correct ans.
  or who are better in it than draw a fig in their head itself
  
  so here height= (6-4) =2
  and base= 3 + 3= 6 (gnore the minus)
  
  so area of the triangle= 1/2 * 2* 6= 6
• 8 years agoHelpfull: Yes(2) No(0)
• 1/2*2*6=6
  
• 8 years agoHelpfull: Yes(0) No(0)
• 6 is ans 1/2*b*h
• 8 years agoHelpfull: Yes(0) No(0)
• 1/2(4*(3+3)+6*(-3-0)+6*(0-3))
  
  =6
• 8 years agoHelpfull: Yes(0) No(0)
• Height = 2
  base 3+3=6
  Area of triangle = 1/2*b*h
  = 1/2*6*2 = 6.
  
  
  Answer is 6
• 8 years agoHelpfull: Yes(0) No(0)
• 12(2*6)
  =6
• 8 years agoHelpfull: Yes(0) No(0)