There is a triangle with sides of any positive integer having area A1. Three squares are drawn with each side. The area of squares are S1, S2, S3 . What is the value of T if T= A1+S1+S2+S3.
Options
a). can be fractional value
b). even or odd
c). even
d). odd

• D) Even Only
  Take any of the pythagorean triplets (3,4,5),(5,12,13),(7,24,25)..e.t.c
  I will consider the first one.. a=3,b=4,c=5
  then T1= 1/2*3*4= 6(always be even for right angle triangle)
  S1= 9(odd)
  S2=16(even)
  S3=25(odd)
  Now T1+S1+S2+S3= 56(even).
  also even+even=even, odd+odd=even
  Similarly for other cases..
  
• 8 years agoHelpfull: Yes(15) No(8)
• consider a triangle with sides (4,4,4)
  then area of the three squares will be an integer.
  and area of the triangle will be {(a)sq* root(3)}/2.
  and root(3) will be a fractional no.
  therefore,
  t1+s1+s2+s3= fractional no
• 8 years agoHelpfull: Yes(12) No(0)
• can be of fractional value depending on the type f traingle u choose..and evn if one calculate the area f a triangle formula is base*height /2..here height is unknown..can be anything..hence (a)
• 8 years agoHelpfull: Yes(6) No(2)
• Answer : A
  Explanation :
  The area of all the three square S1, S2, S3 will always be some integer value but the area of the triangle A1 will not always be an integer.
  
  So there combined sum can be a fractional value
• 8 years agoHelpfull: Yes(4) No(0)
• First point to remember is that we can not take Triangle as an equilateral triangle because it results same area of all the squares drawn on the sides of triangle.
  So, we assume it is a right angle triangle for easy calculation.
  Suppose the sides are 3,4,5 or 6,8,10 or any sides which makes a right angle triangle.
  So area will be (A1)=1/2*3*4=6
  Now area of the squares(S1+S2+S3)= 3 square+4square+5square=50
  So T=50+6=56 even no.
  Ans is C(even)
• 1 year agoHelpfull: Yes(1) No(0)
• b.even or odd
  
• 8 years agoHelpfull: Yes(0) No(5)
• b) even or odd
• 8 years agoHelpfull: Yes(0) No(1)
• Assuming question refers to regular hexagon. We know, in a regular hexagon, all sides are equal (congruent) and each angle is 120°.
  
  
  
  Join the opposite points of a regular hexagon with side a, as shown. We can see that 6 equilateral triangles are formed. All sides are same and hence, longest diagonals of a regular hexagon are twice the length of a side. This concept is explained to make things clear. Back to the question.
  
  Let length of each side be a. In the same diagram we have seen above, it can be observed that distance between parallel sides of a regular hexagon with side a
  = 2 × height of the equilateral triangle with side a
  =2×3√a2=3√a
  
  Using the above relation, we have
  9 = 3√×a where a is the length of each side
  => a = 93√
  
  Question is to find length of the hexagon. Assuming this means the perimeter of the hexagon.
  
  Required length of hexagon = 6a
  6×93√=6×9×3√3√×3√=6×9×3√3=183√
• 8 years agoHelpfull: Yes(0) No(1)
• it is depended upon the property of the triangle... if the triangle is right angled then it should be even..... there is no such condition so answer should be option no (b) i.e even or odd
• 8 years agoHelpfull: Yes(0) No(0)