A regular hexagon is there. The mid points of the sides were joined and formed another hexagon.Then What is the percentage reduction in area.
Asked 13 sept......

• Let ABCDEF be the regular hexagon with sides AB and ED parallel. P and Q are mid points of AF and EF resp.
  AE=root(3) * s (s is side of hexagon)
  then PQ =(root(3) * s)/2 mid point theorem
  Now u know side of inner hexagon
  use formula area of hexagon = (3 * root(3))2 * s^2
  and find diff in area of two hexagon multiply by 100 and divide the product by area of bigger hexagon
  you will get the answer.
  Ans 25%
• 8 years agoHelpfull: Yes(10) No(0)
• area of the bigger hexagon=6*(root(3)/4)*a^2
  for the base of reduce hexagon=2*(root(3)/4)
  side of reduce hexagon =root(3)/2
  area of reduce hexagon=6*(root(3)/4)*((root(3)*a)/2)^2=(9*root(3)*a^2)/8
  diffrece between area=(3*root(3)*a^2)/8
  %reduction=(diffrence beetween area)*100/area of bigger hexagon=25%
• 8 years agoHelpfull: Yes(3) No(0)