Three persons A, B and C separately have some amount of money. If 1/3rd of A's money is equal to 1/4th of B's amount which equals 1/7th of C's money, then at what times of their total amount is equivalent to C's money?

• Let a, b and c be A's, B's and C's money respectively.
  Then their total amount = a + b + c
  Given that, 1/3 rd of a = 1/4th of b = 1/7th of c.
  i.e., a/3 = b/4 = c/7
  Let a/3 = b/4 = c/7 = k
  Then a = 3k, b = 4k and c = 7k
  
  Now, we have to find (a + b + c)/c
  (a + b + c)/c = 3k + 4k + 7k / 7k
  14k / 7k = 2
  i.e., (a + b + c)/c = 2
  (a + b + c)/2 = c
  i.e., 1/2 times of (a+b+c) is equal to c.
  Hence the answer is 1/2.
• 9 years agoHelpfull: Yes(16) No(0)
• a:b=3.:4
  b:c=4:7
  a:b:c=12:16:28
  total =56
  so total money is 2times of c
  
• 9 years agoHelpfull: Yes(13) No(0)
• a:b=3:4
  b:c=4:7
  a:b:c=3:4:7
  considered a variable x
  now
  3x+4x+7x=14x
  let p be a proportional constant .
  14x*p=7X
  k=1/2.
  Ans=1/2.
  
• 9 years agoHelpfull: Yes(6) No(0)
• 43...no idea
  
• 9 years agoHelpfull: Yes(1) No(2)
• ans is 1623.
  
• 9 years agoHelpfull: Yes(0) No(7)
• let x ,y,z be a, b. and c's money. then it is given... (x/3)=(y/4)=(z/7) then....(x/z)=(3/7) and (y/z)=(4/7) so (x+y+z)/z=1+(x/z)+(y/z)=1+(3/7)+(4/7)=14/7=2 so z/(x+y+z)=1/2 ans
• 9 years agoHelpfull: Yes(0) No(0)