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Maths Puzzle
Numerical Ability
A man is known to speak truth 3 out of 4 times. He throws die and reports that it is a 6. The probability that it is actually a 6 is?
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- Prob that its a 6 and he speaks truth :- 3/4 * 1/6 = 3/24
Now what is the prob of reporting a 6 on a dice when it is a lie = 1/4 (speaking a lie) * 5/6 (prob of no. other than 6) * 1/5 (lieing the number as 6 and not telling any othe number except the actual no.) = 5/120 = 1/24
Thus the prob of reporting no. as 6 (total lie + truth) = 3/24 + 1/24 = 4/24 = 1/6
Thus prob of actually having 6 when reported so is = 3/24/1/6 = 3/4(ans)
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- 3/4 = 0.75 is the probability of the person to speak truth.
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