TCS
Company
Numerical Ability
Number System
how many positive integers less than 4300 of digits 0-4.
Read Solution (Total 14)
-
- Ans is 575
one digit no =4 (0 is not a positive integer)
two digit no=4*5=20
three digit no=4*5*5=100
four digit no=3*5*5*5=375(the possibility for 1,2,3 will come in the first position)
four digit no=1*3*5*5(the possibility of 4is fixed in the first position and then 0,1,2 is comes in second position)
and the last digit is 4300 we include this number also
Ans is 4+20+100+375+75+1=575 - 9 years agoHelpfull: Yes(24) No(8)
- ans is 574
one digit no. 4( we can't include 0 because question is for positive integers only so 1,2,3,4 - total 4 numbers)
two digit no. 4*5=20
three digit no. 4*5*5=100
four digit no. 3*5*5*5=375 (upto 3999)
four digit no. 1*3*5*5=75 (from 4000 to 4299)
Answer is 4+20+100+375+75= 574
- 9 years agoHelpfull: Yes(18) No(1)
- Can somebody explain the question clearly and why did you multiply with 5
- 9 years agoHelpfull: Yes(18) No(0)
- ans is 575
one digit no. 5
two digit no. 4*5=20
three digit no. 4*5*5=100
four digit no. 3*5*5*5=375 (upto 3999)
four digit no. 1*3*5*5=75 (from 4000 to 4299)
Answer is 5+20+100+375+75= 575
- 9 years agoHelpfull: Yes(11) No(6)
- is 575
one digit no =4 (0 is not a positive integer)
two digit no=4*5=20
three digit no=4*5*5=100
four digit no=3*5*5*5=375(the possibility for 1,2,3 will come in the first position)
four digit no=1*3*5*5(the possibility of 4is fixed in the first position and then 0,1,2 is comes in second position)
and the last digit is 4300 we include this number also
Ans is 4+20+100+375+75+1=575
- 9 years agoHelpfull: Yes(5) No(0)
- The question itself is not clear
- 9 years agoHelpfull: Yes(3) No(2)
- ans 426
one digit no.-5
two digit no-- 4*5=20
three digit no- 4*5*5=100
4 digit no.=4*3*5*5=300
+1 i.e 4300 - 9 years agoHelpfull: Yes(2) No(4)
- we have to check how many positive integers are formed by {0,1,2,3,4} less than 4300 :
this are the digit 4 digit places : - - - -
in 4300 thr are ones ,tens ,hundreds,thousands,
1) so 1 digit numb take priority of single space so from {0,1,2,3,4} in this 0 is neglected as numbers will
not starts from zero so thr is possibility of 4 numbers in 1st digit i.e {1,2,3,4}
similarly
2)two digit no=4*5=20 {in this starting number will not start with zero but second digit number will be {0,1,2,3,4} so thr is 5 possibility
three digit no=4*5*5=100
four digit no=3*5*5*5=375(the possibility for 1,2,3 will come in the first position)
for given 4300
four digit no=1*3*5*5(the possibility of 4is fixed in the first position and then 0,1,2 is comes in second position)
and last digit 4300 is also added i.e=1
Ans is 4+20+100+375+75+1=575 - 5 years agoHelpfull: Yes(2) No(0)
- ans is 425
one digit no. 4
two digit no. 4*5= 20
Three digit no. 4*5*5= 100
four digit no. 4*3*5*5= 300 (upto 4299)
Four digit no. 4300 = 1
Answer is 4+20+100+300+1 = 425 - 9 years agoHelpfull: Yes(1) No(5)
- One easy method is to notice that there is a one-to-one correspondence between the numbers less than 4300 that can be made from the digits 0–4 and all the numbers less than 43005 in their base-5 representation. The answer is therefore 43005=4×53+3×52=575.
- 9 years agoHelpfull: Yes(1) No(2)
- 4+20+100+375+75=574
- 9 years agoHelpfull: Yes(1) No(1)
- ans is D(4)
- 9 years agoHelpfull: Yes(0) No(1)
- 4+20+100+375+75+1=575
- 9 years agoHelpfull: Yes(0) No(1)
- An=4300,a=1000,d=1,n=?.4300=1000+(n-1)d=3301
- 5 years agoHelpfull: Yes(0) No(1)
TCS Other Question