wo dice are tossed once.what is the probability of getting an even no. on first die or sum is 8,,

• 5/9
  
  Total outcomes=6*6=36
  Number of combinations with even number on first die are (2,1)(2,2),.....(2,6) and (4,1)(4,2).....(4,6) and (6,1)(6,2)......(6,6), Total 6*3=18
  Number of combinations with sum 8 are (2,6) (3,5) (4,4) (5,3) (6,2),Total=5 and among these (2,6) (4,4) (6,2) are already included in the earlier combinations of even number on first die, so remaining 2 i.e (3,5) (5,3)
  So probability of getting an even number on first die or sum 8=(18+2)/36=20/36=5/9
• 9 years agoHelpfull: Yes(17) No(2)
• (18/36)+(5/36)-(3/36)=5/9
• 7 years agoHelpfull: Yes(2) No(0)