two sides of a plot measure 48m 64m and the angle between them is a right angle.the other two sides measure 50m each and the other three angle are not right angle.if the plot is not convex what is the area of the plot

• area of 1st triangle =1/2*64*48=1536
  hyp of 1st triangle=root under 48^2+64^2=80
  2nd triangle is isosceles so height =sqrt 2500-1600=30
  so are of 2nd triangle=1/2*80*30=1200
  so total area=1536+1200=2736
  
• 8 years agoHelpfull: Yes(11) No(1)
• Total area of plot is : 1200+1536 = 2736
• 8 years agoHelpfull: Yes(4) No(4)
• let us divide the area in two triangles..
  
  one right angled with base & height as 48 m & 64m.. i.e. the hyp = root(48^2+64^2) = 80m.. thus area = .5*48*64 = 1536 sq m
  
  second one is isosceles with base = 80m (the hyp of the prev triangle) & the remaining two sides 50m each.. thus area = .5*80*50=1200 sq m
  
  hence total area = 1536+1200 = 1736 sq m
• 8 years agoHelpfull: Yes(4) No(4)
• total area=3420sq m
• 8 years agoHelpfull: Yes(0) No(3)
• one right angled triangle,its sides as 48m and 64m ..its hyp=80m thus area =(1/2)*48*64=1536 sq m
  
  second one isosceles with base as 80 m and remaining sides as b=50 m each ...its area =(1/2)*b*h...as h=Root(50^2 -(1/4)*80^2)=30 hence its 2nd area =(1/2)*50*30=750 sq m
  Hence total area =1536+750=2286 sq m
  
• 8 years agoHelpfull: Yes(0) No(2)
• since its not a convex polynomial
  therefore the area=64*48/2-30*80/2=336 sq.m
  
• 8 years agoHelpfull: Yes(0) No(0)