he Range of the function f(x) = (x - 2) / (2 - x) is
A) -1 to 1
B) 0 to 1
C) -1 to 0
D) None of above

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• -1 to 0
  
  f(2) = (2 - 2)/(2 - 2) = 0/0 = 0
  f(1) = (1 - 2)/(2 - 1) = -1/1 = 1
  
• 9 years agoHelpfull: Yes(6) No(7)
• D) NONE Of THESE
  
  f(x) = 2-x/x-2 = (2-x)(2-x)/(x-2)(2-x) = (2-x)^2 / (-1) (2-x)^2 = -1
  
  so , right answer is -1.
• 9 years agoHelpfull: Yes(5) No(1)
• f(x)=(x-2)/(2-x)
  for x=-1, f(-1)=-1; for x=0, f(0)=-1;
  for x=-2,f(-2)=-1; for x=1,f(1)=-1;
  similarly for all negative values of x f(x)=-1; similarly for all positive values of x the output will be -1 except at x=2 the value is undefined;
  so the range of f(x) "-∞ to +1 and +3 to +∞"
  answer is D. None of The Above
• 9 years agoHelpfull: Yes(5) No(2)
• D) because -(2-x)/(2-x)=-1
  -1 is constant which is independent of x, so range is -1.
• 9 years agoHelpfull: Yes(4) No(0)
• SoLution pls
• 9 years agoHelpfull: Yes(0) No(0)
• d. None of these
• 9 years agoHelpfull: Yes(0) No(0)
• f(x)=(2-x)/(x-2)=-1
  f(x) is a constant function ..its range is -1,when x!=2
• 9 years agoHelpfull: Yes(0) No(1)
• f(x)=(x-2)/(2-x)
  where,x=0,+-1,+-2,+-3,...infinite
  x=0,f(x)=-1, x=1,f(x)=-1, x=-1,f(x)=-1, x=2,f(x)=0, x=-2,f(x)=-1, x=3,f(x)=-1, x=-3,f(x)=-1
  therefor, this is the ans option C
• 9 years agoHelpfull: Yes(0) No(1)