MBA Exam

Let S be the set of 5 digit numbers formed by the digits 1,2,3,4 and 5, using each digit exactly once such that exactly two odd positions are occupied by odd digits. What is the sum of the digits in the rightmost position of the numbers in S?

1) 228
2) 216
3) 294
4) 192

Read Solution (Total 1)

When the last digit is odd there are 16 allowable combinations. The sum of odd last digits is 5+3+1=9.

When the last digit is even there are 12 allowable combinations. The sum of even last digits is 4+2=6.

Sum of last digits = (16*9)+(12*6)
=216.
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MBA Other Question

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1) 336
2) 426
3) 486
4) none of these
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1) 1
2) 2
3) 3
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