C Programming and Technical Programming Technical

main()
{
char str = "12345";
printf("%c %c %cn", str, (str++), (str++));
}

Read Solution (Total 4)

We will get a garbage value printed as the output.
EXPLANATION: *str indicates the value stored at the address in str, So str++ is the incremented address of str,which points to a memory location containing any random/garbage value.
So *(str++) will print that garbage value.
9 years agoHelpfull: Yes(1) No(0)

9 years agoHelpfull: Yes(0) No(0)
o/p : Error
Reason : We can't change the base address of the string.
9 years agoHelpfull: Yes(0) No(0)
output will be:
3 2 1
because it is stack operation.it operates on LAST IN FIRST OUT and it is evaluated from
RIGHT to LEFT.
9 years agoHelpfull: Yes(0) No(1)

C Other Question

#include
void main()
{
float p;
p=3.2:
printf("p/2*6",%d):
} main()
{
char *str = "12345";
printf("%c %c %cn", *str, *(str++), *(str++));
}