main()
{
char *str = "12345";
printf("%c %c %cn", *str, *(str++), *(str++));
}

• The contents in printf are stored in the form of stack. So first right most variable i.e *(str++) is executed which prints '1' and address gets incremented.next *(str++) executes which prints '2' and finally executes*str which prints '3'.printing of values is done same as given in the printf function.
  So output is 321.
• 8 years agoHelpfull: Yes(3) No(0)
• pls explain clearly the output of pgm
• 8 years agoHelpfull: Yes(1) No(0)
• {
  char *str = "12345";
  printf("%c %c %cn", *str, *(str++), *(str++));
  }
• 7 years agoHelpfull: Yes(1) No(0)
• str gives startin address of string
  str++ gives 1st position after start
  and again str++ gives second position from start
  so the answer i think is 123
• 8 years agoHelpfull: Yes(0) No(0)
• The output of d given program z 3 2 1.Bcoz execution/operation strats from right to left.
• 8 years agoHelpfull: Yes(0) No(0)
• Answer will be 3 2 1
• 8 years agoHelpfull: Yes(0) No(0)
• in string we have to take "12345" then why you take only 1 instead of all it means "12345"
• 8 years agoHelpfull: Yes(0) No(0)