How many different integers can be expressed as the sum of three distinct numbers from the set
{3, 8, 13, 18, 23, 28, 33, 38, 43, 48}?

• 22
  No of terms = {(last - first )/ (difference)} + 1
  ={(129 - 24) / 5 } +1
  =22
  
• 8 years agoHelpfull: Yes(8) No(4)
• From first set of integers sum of3+8+13=24
  Last set sum of 38+43+48=129
  So all integers expressed should be in between 24 and 129.
  And all sum of integers have unit place of 9 and 4 so ...no.of itegers=(129-24)/(9-4)=21
  Ans:21
  
• 8 years agoHelpfull: Yes(6) No(4)
• 53....The given series is alternate differance of 10..
• 8 years agoHelpfull: Yes(2) No(1)
• 10 p 3=720 is answer
• 8 years agoHelpfull: Yes(1) No(1)
• since we have to select combination of 3 distinct nos.
  So , ans is 10c3=120
• 8 years agoHelpfull: Yes(1) No(1)
• sala jisne iss side ko banaya h wo bhi chutiya h , campusgate se seekho kuch , answer sahit h wo ,
• 8 years agoHelpfull: Yes(0) No(2)
• Simply 10c3
• 8 years agoHelpfull: Yes(0) No(1)
• 24,.......,129
  24-29- 2 nos
  30-39- 2 nos
  .
  .
  .
  last 120-129- 2
  total= 24
  
• 8 years agoHelpfull: Yes(0) No(1)
• L-a/d+1=129-24/5+1=25+1=26...l=largest of three numbers 48,43,38...a=smallest of 3 numbers..
• 8 years agoHelpfull: Yes(0) No(0)