if a ladder is 100m long and distance between bottom of a ladder and wall is 60m. what is the maximum size of the cube that can be placed between the ladder and wall

• Hypoteneus = 100 and base is 60 so perpen will be 80..
  Now putting a cube inside gives two similar triangles....
  Comparing perp to the base ratio we get
  80/60 = (80-x)/x where x is side of the cube. Solving we get x= 34.28
• 8 years agoHelpfull: Yes(24) No(4)
• ans= 30
• 8 years agoHelpfull: Yes(0) No(7)
• The answer is 35. it is a simple pythagorus thm problem.let the edge of cube be x. now make a square between a right angled triangle of base 60 hypotnuse 100 and height is calculated to be 80. now due to square two right triangles are formed. so the hypo of 1st tri. + hypo. of 2nd tri. should be equal to 100.
  therefore (60-x)^2 +x^2 + x^2 + (80-x)^2 = 100.
• 8 years agoHelpfull: Yes(0) No(4)
• Size of cube in right angle triangle= 60*80/60+80
  =4800/140
  =32.28
• 3 years agoHelpfull: Yes(0) No(0)