A sum of 1400 is divided amongst A, B, C and D such that A's share : B's share = B's share : C's share = C's share : D's share = 3/4. How much is C's share?

• 384 Rs.
  
  A/B=B/C=C/D=3/4
  If share of A: B: C: D= 27x : 36x : 48x : 64x
  As 27x+36x+48x+64x=1400, x=8, so C's share=48*8=384
• 9 years agoHelpfull: Yes(1) No(1)
• @Vinod Kumar
  
  Take successive ratios as
  A:B=3x:4x
  A:B:C=9x:12x:16x
  A:B:C:D=27x:36x:48x:64x
  
  OR
  Follow the method of converting all the ratios in terms of any one(*here solved for A)
  A/B=3/4 or 4A=3B,B=4A/3 ---(i)
  B/C=3/4 or 4B=3C, Substituting B from (i),4*4A/3=3C, C=16A/9 ---(ii)
  C/D=3/4 or 4C=3D, Substituting C from (ii),4*16A/9=3D, D=64A/27 ---(iii)
  As A+B+C+D=1400
  Substitute the values of B,C & D in terms of A, we have
  A + (4A/3)+(16A/9)+(64A/27)=1400, A=216
  So C=16*216/9=384
• 9 years agoHelpfull: Yes(1) No(0)
• a:b:c:d=27:36:48:64
  explain??
• 9 years agoHelpfull: Yes(0) No(0)
• thank you @devendra
• 9 years agoHelpfull: Yes(0) No(0)