ABC
FED
------------------------
HEBG
HCJC
HHDJ
---------------------------
HBAEDG

• Solve by C*E=C
  6*2=12,6*4=24,6*8=48
  234
  567
  --------------
  1638
  1404
  1170
  ------------
  132678
• 9 years agoHelpfull: Yes(5) No(1)
• 1) c*e=c it means 6*2=12,6*4=24, 6*8=48
  2) h+h is not give carry it means h =1,2,3,4 not more than 4 bz 5+5=10 its generate carry
  3) e+j+j=e in this case may be j=0
  
  234
  567
  ............
  1638
  1404
  1170
  ...........
  132678
  
• 9 years agoHelpfull: Yes(3) No(0)
• 1) h+h=b,so h=1,2,3,4.....h have no carry
  2)E*c=c....so put there 6*2 or6*4 or 6*8
  now ,we put 6*2 ,thn it fail
  again we put 6*4 and H=1 and H+H+c1=B.so B=3..
  thn we get solution...
  
  234
  567
  --------------
  1638
  1404
  1170
  ------------
  132678
  --------------
• 9 years agoHelpfull: Yes(1) No(0)
• As C*E=C . So,for this equation 2*6=12; 4*6=12; 8*48 will be applicable.E will be 6 for sure.
  Now if we select 2*6=12. We will stuck in doing the multiplications with E.
  So we will select 4*6=24.
  Now, As E+J+J=E ,So E will definitely 0 or 5.
  As 4 & 6 are already booked and 1 can't be B . So, we start with 2 . As it will not fit in our criteria As J should come 0 or 5. So, B will be 3, it fulfills our requirement .
  Since H+H+carry=B. Hence H==1.
  as we know the value of E & C and we know the carry for that equation will be 2 , So solve the equation A*6+2=14.From this A will come 2.
  On the solution we can see the equation H+C+D=A . We can put all the values then D will come 7.
  Now, Only 0,5&9 digits are left over there.
  F can't be 0.
  So,start with 5 and it will fulfill our all solution.
  2 3 4
  *5 6 7
  ----------
  1 6 3 8
  1 4 0 4
  1 1 7 0
  -------------
  1 3 2 6 7 8
• 9 years agoHelpfull: Yes(1) No(0)
• 234
  567
  take J=0 and E=6
  bcz J+J+E+[C]=E so J+J+[c]=10 so j wil be 0 or 5 but 5 is not possible here bcz E*C=C
• 9 years agoHelpfull: Yes(0) No(0)
• 9 6 7
  *6 8 76
  -----------
  6 7 6 9
  7 7 3 6
  5 8 0 2
  ---------------
  6 6 3 3 2 9
• 9 years agoHelpfull: Yes(0) No(1)
• 234
  567
  _____
  1638
  1404
  1170
  _______
  132678
• 9 years agoHelpfull: Yes(0) No(0)