In this equation , A^B means A raised to the power B. If f(x)= ax^4 + bx^4 + x + 5.
If f(-3) = 2 then f(3) = ?

• f(-3)=2=ax^4+bx^4+x+5
  =>2=81a+81b+2
  =>81(a+b)=0
  hence a+b=0
  now f(3)=81a+81b+3+5
  =>f(3)=81(a+b)+8
  =>f(3)=81*0+8
  =>f(3)=8 ans
• 8 years agoHelpfull: Yes(25) No(0)
• f(-3)=2
  f(-3)=a(-3)^4+b(-3)@^2+(-3)+5
  . =81a+9b+2=2.
  Or, 81a+9b=0.
  Now f(3)= a(3)^4+b(3)^2+3+5.
  . =81a+9b+8=0+8=8.
  So f(3)=8.
• 8 years agoHelpfull: Yes(2) No(0)
• 81a+81b=0
  therefore f(3)=0+3+5=8
• 8 years agoHelpfull: Yes(1) No(1)
• f(-3)=81a+81b-3+5=2
  81a+81b+2=2
  81a+81b=0
  81(a+b)=0
  a+b=0
  f(3)=81a+81b+3+5
  81(a+b)+8
  81(0)+8=8
• 8 years agoHelpfull: Yes(1) No(0)
• f(-3)=81a+81b+2=2
  81a=-81b
  a=-b
  f(3)=81a-81b+3+5
  f(3)=8 ans
• 8 years agoHelpfull: Yes(1) No(0)
• F(3) must be 8
• 8 years agoHelpfull: Yes(0) No(1)
• f(-3)=81a+81b+2
  here 81a+81b is constant
  f(3)=81a+81b+8
  so here 81a+81b also constant
  
• 8 years agoHelpfull: Yes(0) No(0)
• if f(-3)=a(-3)^4+b(-3)^4+(-3)+5
  =81a+81b+2
  =2 (since 81a+81b=constant)
  likethat only
  f(3)=81a+81b+3+5
  =81a+81b+8
  =8
• 8 years agoHelpfull: Yes(0) No(0)
• f(-3)=a(-3)^4 +b(-3)^4+(-3)+5
  on solvng,
  a+b=0
  f(3)= a(3)^4+b(3)^4+8
  = 8
• 8 years agoHelpfull: Yes(0) No(0)
• Explanation:
  f(-3) = a(-3)4 + b(-3)4 + (-3) + 5 = 81a +81b + 2 = 2 So 81a +81b = 0
  f(3) = a(3)4 + b(3)4 + (3) + 5 = 81a +81b + 8
  Substituting the value of 81a +81b = 0 in the above we get f(3) = 8
• 8 years agoHelpfull: Yes(0) No(0)
• f(-3)=81a +81b-3+5=2,hence 81(a+b)=0
  now f(3)=81(a+B)+3+5=0+8=8
  =>ans =8.
• 8 years agoHelpfull: Yes(0) No(0)
• if we put -3 at a place of X ,we see that a * (-3)^4 + b * (-3)^4 + (-3) +5
  here 1st two term are equal if a= -b and that case last two term =2,
  so that f(3)= 3+5=8 is ans
• 8 years agoHelpfull: Yes(0) No(0)
• f(-3)=91(a+b)=0
  f(3)=91a+91b+3+5 put the value of 91(a+b)=0 then we get
  f(3)=0+8 ans
  
• 8 years agoHelpfull: Yes(0) No(0)
• f(-3)=(a+b)x^4+x+5 then
  2=81(a+b), (a+b)=1/27
  f(3)=8
• 8 years agoHelpfull: Yes(0) No(0)
• given f(-3)=2
  by solving it we get a(-3)^4+b(-3)^4-3+5=2
  81a+81b=4
  a+b=4/81
  f(3)=81a+81b+8
  =81(4/81)+8
  =12
• 5 years agoHelpfull: Yes(0) No(1)