a 3 7 10 8 4 12 0 5 5 3 2 Ans Divide the 3 elements into one group

p) 8-5=3 3^2=9
7-2=5 5^2=25
5-1=4 4^2=16
8-6=2 2^2=4
so answer 4
9 years agoHelpfull: Yes(17) No(0)

g)2,6,5,14,11,26,17,?

ans is 38

here we are multiply with 2 the alternate prime numbers

2 , (3*2)=6 , 5 , (7*2)=14 , 11 , (13*2)=26 , 17 , (19*2)=38
8 years agoHelpfull: Yes(14) No(0)
n) 1) 18+3=21-4=17+7=24; (18, 21, 17, 24)
2) 24+3=27-4=23+7=30 (24, 27,23, 30)
3) 5+3=8-4=4+7=11 (5, 8, 4, 11)
So the missing number is 11.
9 years agoHelpfull: Yes(11) No(0)
b) answer is 3.5
decide the numbers in series ,
0. 1. 1. 2. 0.5
2. 2. 4. 2. 2
4. 3. 7. 2. ?
in this take first row 0 (0+2=2)
2(2+2=4)
4
again consider 2 and row 1,2,3( difference b/w each no is 1)..so repeat the same process for all the rows ,last row (0.5,2,?)
ans:-0.5+1.5=2
2+1.5=3.5
9 years agoHelpfull: Yes(10) No(4)
c) 1,1,2,4,6,36,39,1521,?

ans is 1525

(1,1),(2,4),(6,36),(39,1521),(?)

1*1=1 ---> add 1 to result 1+1=2

2*2=4 ---> add 2 to result 4+2=6

6*6=36 ---> add 3 to result 36+3=39

39*39=1521 --> add 4 to result 1521+4=1525

e) 2,9,5,49,11,169,?

ans is 17

here we are square the alternate prime numbers

2 3*3=9 5 7*7=49 11 13*13=169 17

f) 49,7,98,16,4,48,9,3,36,25,5,?

ans is 125

divide into groups (49,7,98),(16,4,48),(9,3,36),(25,5,?)

in first group to get 2nd num divide 49/7=7

to get 3rd num divide 49*2=98

in second group to get 2nd num divide 16/4=4

to get 3rd num divide 16*3=48

in third group to get 2nd num divide 9/3=3

to get 3rd num divide 9*4=36

in fourth group to get 2nd num divide 25/5=5

to get 3rd num divide 25*5=125

g) 2,6,5,14,11,26,17,?

ans is 39

divide 2 num as pair (2,6),(5,14),(11,26),(17,?)

6-2= 4 add 5 to get next pair diff 4+5=9

14-5=9 add 6 to get next pair diff 9+6=15

26-11=15 add 7 to get next pair diff 15+7=22

here we don't know x, but we know result of next pair

x-17=22 on solving this equation we get x=39

l) 13,24,36,23,34,56,33,44,96,43,54,?

divide numbers as (13,24),36,(23,34),56,(33,44),96,(43,54),(?)

24-13=11 36 34-23=11 56 44-33=11 96 54-43=11 ?

11 36 11 56 11 96 11 ?

from the above series diff b/w alternate numbers are

56-36=20

96-56=40=20*2

x-96=80=40*2 ---> on solving we get x=176
9 years agoHelpfull: Yes(9) No(6)
o) 3+5+2=10*10=100
4+7+3=14*14=196
1+6+5= 12*12=144
9 years agoHelpfull: Yes(9) No(0)
2,3,10,15,26..?
1 * 1 = 1+1 = 2
2 * 2 = 4-1= 3
3 * 3 = 9 + 1 = 10
4 * 4 = 16 - 1 =15
5 * 5 = 25+1 =26
6 * 6 = 36 - 1 =35
9 years agoHelpfull: Yes(9) No(2)
R) (1/4)*1=1/4;
(1/4)*2=1/2;
(1/2)*3=3/2;
(3/2)*4=6;
6*5=30;
answer is 30;
9 years agoHelpfull: Yes(9) No(0)
h) 7+0+1=8
5+12+9=26
3+23+5=28
9 years agoHelpfull: Yes(6) No(0)
c)1,1,2,4,6,36,39,1521,?
........1525
9 years agoHelpfull: Yes(4) No(2)
j) 5,16,22,68,28,87,36,106,11,?
It will be:
5
(5*3)+1=16
22
(22*3)+2=68
28
(28*3)+3=87
36
(36*3)+4=112(it will not 106 according to the sequence)
11
(11*3)+5=38
8 years agoHelpfull: Yes(4) No(0)
g) 2,6,5,14,11,26,17
divide it into pairs
(2,6) (5,14)(11,26)(17,?)
2=2 6=6
5=2^2+1 14=6*2^1 +2
11=2^3+1 26=6*2^2 + 2
17=2^4+1 so 6*2^3 + 2 =48+2 =50
so next number is 50
9 years agoHelpfull: Yes(2) No(7)
e)2,9,5,49,11,169,?
it will be 17...because 2,3^2,5,7^2,11,13^2,17,19^2 series of all prime numbers.
8 years agoHelpfull: Yes(2) No(2)
l)Right series is-13,24,36,23,34,56,33,44,76,43,54,??
--------------------------------------------------------------------------------
ANS-96
solution a) divide series into 4 parts-
(13,24,36)(23,34,56)(33,44,76)(43,54,?)
13+24=37-1=36
23+34=57-1=56
33+44=77-1=76
hence next series is-43+54=97-1=96
-----------------------------------------------------------
solution b)Divide series into 4 parts like above -
13+11=24,24+12=36
23+11=34,34+22=56
33+11=44.44+32=76
hence next series is-
43+11=54,54+42=96
8 years agoHelpfull: Yes(2) No(0)
ans=8;
three group (0,1,1,2,0.5) ( 2,2,4,2,2) (4,3,7,2,_)
1st group( 0+1=1,2,0.5)
2nd group (2+2=4,2,0.5*4=2)
3rd group (4+3=7,2,2*4=8)
9 years agoHelpfull: Yes(1) No(3)
n) 24-18=6-1=5
27-21=6+2=8
23-17=7-3=4
30-24=6+4=10
9 years agoHelpfull: Yes(1) No(9)
h)and:-28
divide into groups (7,0,1)(8,5,12)(9,26,3)(23,2,?)
adding first GRP numbers I.e 7+0+1=8 ,gives first no in second GRP,in the same way 5+12+9=26 gives 2nd no value in 3 rd series.....
by following this we will get 3 rd no value in 4 the series which is unknown to us....3+23+2= 28
9 years agoHelpfull: Yes(1) No(0)
q) -3,6,1,-2,4,-1,-1,2,-3,?
(-3,6,1)
(-2,4,-1)
(-1,2,-3)
(0,0,-5)
so the ans is 0
8 years agoHelpfull: Yes(1) No(0)
M) divide them in 3 containing 4 elements each.i.e,
(0,1,2,0.5) (2,2,2,2) (4,3,2,?)
Now, add first 2 nos and divide by third no.
=> (0+1)= 1/2= 0.5
=> (2+2)= 4/2= 2
=> (4+3)= 7/2= 3.5 ans.
7 years agoHelpfull: Yes(1) No(0)
j) 5,16,22,68,28,87,36,106,11,?
divide the series.......(5,16),(22,68),(28,87),(36,106),(11,?)

5*3 +1=16
22*3 +2=68
28*3 +3=87
36*3 -2=106
11*3 -1=32
ans: 32
8 years agoHelpfull: Yes(0) No(5)
e)23
the 1st is
8 years agoHelpfull: Yes(0) No(0)
n) 18,24,5,21,27,8,17,23,4,24,30,??
24-18=6-1=5
27-21=6+2=8
23-17=6-2=4
30-24=6+3=9
7 years agoHelpfull: Yes(0) No(0)
can any one send the answer the for r?
7 years agoHelpfull: Yes(0) No(0)
k) 7776=6^5
625=5^4
64=4^3
9=3^2
so the next number is 2^1=2
7 years agoHelpfull: Yes(0) No(0)
d) 7-3=4
6-3=3
4.5-3=1.5
2.25-3= -0.75
so ans= -0.75
7 years agoHelpfull: Yes(0) No(0)

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