Elitmus
Exam
Numerical Ability
Number System
x,y odd z is even
((x^2+y^2)z^2)/8 is
A)even b)odd c) either even or odd d)fraction
Read Solution (Total 11)
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- ((15^2+13^2)14^2)/8=((225+169)196)/8=(394)196/8=197*49=9653(odd no)
((3^2+5^2)4^2)/8=68(even no)
so ans is C either even or odd
- 9 years agoHelpfull: Yes(20) No(3)
- c) either even or odd
one thing is sure that the above expression is divisible by 8 because (odd+odd)=even and even*even=even
above expression will contain atleast three 2's in multiplication.
Now.. we can see that when a no such as 24/8 gives 3 and 48/8 gives 6.. hence above expression can also give even or odd value. - 9 years agoHelpfull: Yes(7) No(2)
- when any number is divided by 8 it can be odd or even...
ans: C - 9 years agoHelpfull: Yes(4) No(2)
- Option is c....
- 9 years agoHelpfull: Yes(3) No(0)
- Any number which is a squre of even number is divisible by 4....
Squre of any odd digit is odd and some of two odds is even..
So, the resultant number would be divisible by 8.....
Now after dividing we will be having one odd/even and one even digit whose product is always even....
So the answer is a - 9 years agoHelpfull: Yes(1) No(5)
- ans is: even
taken for example 3,5 as x and y
8 as z then after solving it we get an even no - 9 years agoHelpfull: Yes(1) No(3)
- c ,either even or odd
take
x=1 ,y=3 z=2
(1^2+3^2)*2^2=40/8=5
take x=7,y=9 z=4
130*16/8=even
- 9 years agoHelpfull: Yes(1) No(0)
- we know that :
(even)^ 2= even
(odd)^2 = odd
even+odd=odd
odd* even=odd and even - 8 years agoHelpfull: Yes(1) No(0)
- as given that x and y are odd nos and z is even no
so,x exponential 2 would be odd
similarly,y exponential 2 would be odd.
and z exponential 2 would be even
so,(odd+odd)*even/even must be an even no.so A will be the correct option. - 9 years agoHelpfull: Yes(0) No(2)
- odd is ans
let x=3,y=5,x=2
(9+25)4/8
(34*4)/8
17(odd)
- 9 years agoHelpfull: Yes(0) No(5)
- ans is either ever or odd
- 8 years agoHelpfull: Yes(0) No(0)
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