Two identical cubes if one of them is painted pink on its 4 side and blue on the remaining two side then how many faces painted pink to other cube so that probability of getting cube is 1/3 when we roll both the cube.

• 0 faces should be painted pink i.e all faces blue
• 9 years agoHelpfull: Yes(22) No(2)
• Ans. 3faces
  1/3=4/6*(probability of getting pink on second cube)
  (probability of getting pink on second cube)=1/2
  which we will get if we paint 3 out of 6 faces pink.
• 9 years agoHelpfull: Yes(9) No(9)
• probablity of getting pink face = 1/3 = probablity of getting pink on one * probablity of getting pink on other (4/6*x/6).
  where x = no of pink colour faced in second cube
  x = 3
• 9 years agoHelpfull: Yes(6) No(2)
• let the second box be painted with pink x sides , thus (6-x) sides are painted blue.
  We will have same colour when either both cubes show Pink or both blue;
  As per question,
  (4/6)*(x/6)+(2/6)*(6-x)/6=1/3
  On solving you get a value of x=0;
  So no sides in the 2nd cube was painted pink
• 9 years agoHelpfull: Yes(6) No(0)
• 1/2*4/6 + 1/2 * (no. of pink faces on 2nd cube/6) = 1/3
  
  => 1/3 + x/12 =1/3
  
  => x= 0
  so no of pink face on second cube = 0 Ans.
• 9 years agoHelpfull: Yes(2) No(0)
• * getting pink face painted is 1/3( correction in question)
• 9 years agoHelpfull: Yes(1) No(2)
• can anyone say what wl be the ans of ds qus.........
• 9 years agoHelpfull: Yes(1) No(3)
• Question was like...probablity of getting same colour is 1/3....
  
  If 2nd cube has 0 pink faces , that means 6 bile faces...
  
  1st cube = 4 pink , 2 blue
  2nd cube = 0 pink , 6 blue
  
  On 1st cube its alwas blue = 1
  
  2nd cube , probablity of getting blue is =2 / 6 = 1/3 Ans
• 9 years agoHelpfull: Yes(1) No(1)
• Explanation:
  First cube has got 4 pink sides and 2 black sides.
  Let the other cube got x sides pink and (6 - x) sides black.
  Now when we roll both the dice, we can either pink on both cubes or black on both cubes.
  Probability = 46×x6+26×6−x6=13
  =4x+12−2x36=13
  ⇒x=0
  So second cube should not have any pink faces at all.
• 9 years agoHelpfull: Yes(1) No(0)
• here goes my solution guys.Please correct me if i am wrong. Let 'a' number of face of the second cube be painted pink.Now we have for possible outcome
  case 1:-pink on both the cubes.
  case 2:-pink on 1st cube and not a pink face on second cube.
  case 3:-blue on first cube and pink on second cube
  case 4:-blue on 1st cube and not pink on second cube.
  so for case 1: probability=4/6 *a/6
  case 2:-probability:-4/6*(1-a/6)
  case 3 :-probability= 2/3*a/6
  case 4:- probability:- 2/6*(1-a/6)
  so required probabilty:- case 1/(case 1+case 2 +case 3+ case 4) which is equal to 1/3
  solving the equation we get a=3 i.e 3 faces of the second cube must be pink.
  please correct me if i am wrong.
• 9 years agoHelpfull: Yes(0) No(9)
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• 9 years agoHelpfull: Yes(0) No(4)
• 4.5@@@@@@farhat
• 9 years agoHelpfull: Yes(0) No(3)