What are the last three number of this series 11234783131?
Star mark question.

• 23-11= 12
  47-23=24
  83-47=36
  131-83=48
  Thus all differences are multiple of 8.
  so, 131+60=191
• 9 years agoHelpfull: Yes(28) No(3)
• common differnce in series is multpiles of 12 so add 60 to 131 then answer is 191
• 9 years agoHelpfull: Yes(21) No(1)
• 11+12=23
  23+24=47
  47+36=83
  83+48=131
  131+60=191
• 9 years agoHelpfull: Yes(6) No(1)
• 529 will be in the series
• 9 years agoHelpfull: Yes(1) No(2)
• 11234783131. if we see the numbers we can find 23-11=12
  47-23=24
  83-47=36
  131-83=48
  so next number will be 131+60=191(multiple of 12) . so the last 3 digits are 191.
• 9 years agoHelpfull: Yes(1) No(0)
• ???????????????
• 9 years agoHelpfull: Yes(0) No(2)
• ans is 91
  
• 9 years agoHelpfull: Yes(0) No(0)
• the ans is 191 the difference between the no is in 12,24,36,48 so in order to get next one 60 should be added
• 9 years agoHelpfull: Yes(0) No(0)
• Difference is 12*n
• 9 years agoHelpfull: Yes(0) No(0)
• 23-11=12
  47-12=24
  83-47=36
  131-83=48
  as all the differences are the multiples of 12 ,next num will be 60.so x-131=60
  x=131+60=191
• 9 years agoHelpfull: Yes(0) No(1)
• 191 is number
  23-11=12
  47-23=24
  83-47=36
  131-83=48
  so next step is
  131 + 12*5=191
• 9 years agoHelpfull: Yes(0) No(0)
• 11+12*1=23
  23+12*2=47
  47+12*3=83
  83+12*4=131
  131+12*5=160
• 9 years agoHelpfull: Yes(0) No(0)
• sry i did a mistake before
  the final answer is 191
  131+12*5=191
• 9 years agoHelpfull: Yes(0) No(0)
• 11+12*1=23
  23+12*2=47
  47+12*3=83
  83+12*4=131
  131+12*5=191
• 9 years agoHelpfull: Yes(0) No(0)
• 162
  difference between first 2 number is 12,next 2 number is 24.and so on
• 8 years agoHelpfull: Yes(0) No(1)
• ANSWER IS 191
  23-11= 12
  47-23=24
  83-47=36
  131-83=48
  Thus all differences are multiple of 8.
  131+60=191
• 8 years agoHelpfull: Yes(0) No(0)
• series 11,23,47,83,131 ......
  11
  11 + 12 = 23
  23 + 24 = 47
  47 + 36 = 83
  83 + 48 = 131
  131 + 60 = 191
  191 + 72 = 263
• 6 years agoHelpfull: Yes(0) No(0)