There are 4 boxes colored red, yellow, green and blue. If 2 boxes are selected, how many combinations are there for at least one green box or one red box to be selected ?

• 5
  
  Selecting 2 from R,Y,G,B= (RY) (RG) (RB) (YG) (YB) (GB)
  So combinations with at least one green or one red box are (RY) (RG) (RB) (YG) (GB), Total=5
• 9 years agoHelpfull: Yes(13) No(0)
• answer=1
  
  There are total 4 boxes and we have to select 2 boxes...
  so the total no. of outcomes is =4C2
  no. of favourable outcomes is=>
  for atleast one Green box=1C1 X 3C1 (where 1c1 is for selecting green box...and 3c1 is for second box which can be of from any of the three colors)
  Similarly for atleast one Red =1C1 X 3C1
  So the required probablity= (1C1 X 3C1)+ (1C1 X 3C1)/4C2= 1 ans.
• 9 years agoHelpfull: Yes(5) No(10)
• Answer is 5
• 9 years agoHelpfull: Yes(3) No(0)
• ans-5
  3c1+2c1=5
  
• 9 years agoHelpfull: Yes(1) No(0)
• correct answer is 5.
• 9 years agoHelpfull: Yes(0) No(0)
• Ans= 5
  combinations may be->RY, RB, RG, GY, GB
  so total combinations are 5
• 9 years agoHelpfull: Yes(0) No(0)
• 1*3c1 + 1*3c1 = 6 is the right answer
• 9 years agoHelpfull: Yes(0) No(1)
• 6
  
  RY ,RG,RB,GY,GB,GR
• 9 years agoHelpfull: Yes(0) No(0)