7 members have to be selected from 12 men and 3 women ,Such that no two women can come together .
In how many ways we can select them ?

• since no two women can come together,therfore women can be selected in 3c1 ways ...and men will be chosen in 12c6 so to complete the 7 group members...
  =12c6*3c1
  and only selection of men also possible = 12c7
  
  so final ans : 12c6*3c1 + 12c7
• 9 years agoHelpfull: Yes(36) No(1)
• since no two women can come together,therfore women can be selected in 3c1 ways ...and men will be chosen in 12c6 so to complete the 7 group members...
  so the answer would be=12c6*3c1
• 9 years agoHelpfull: Yes(28) No(9)
• step1) selecting random 7 person = 15c7
  
  Step2)finding those cases when 2 women are together i.e (WW)_ _ _ _ _
  which is equal to
  3c2*13c5 (selecting 2 random women that will be together * selecting any 5 random people from l left 13)
  
  Step3) subtacting those cases when 2 women are together from 15c7 ....
  so 15c7 - (3c2 *12c5)
  
• 9 years agoHelpfull: Yes(12) No(0)
• THE QUESTION HAS ASKED TO SELECT THE OUTCOME NOT ARRANGE SO ONLY 2 CASES 12C7(WHEN NO WOMEN SELECTED)+ 12C6*3C1(WHEN 1 WOMEN SELECTED)
• 9 years agoHelpfull: Yes(4) No(0)
• when 0 women selected between 7 member
  total number of ways of selection=12c7-----(1)
  when 1 women selected between 7 member
  total number of ways of selection=12c6*3c1-----(2)
  when 2 women selected between 7 member
  total number of ways of selection=12c5*3c2-6------(3)
  here 6 is total number of selection of two women together
  when 3 women selected between 7 member
  total number of ways of selection=12c4*3c3-5-6--------(4)
  here 5 is total number of selection of 3 women together
  so the total number of selection way=(1)+(2)+(3)+(4)
• 9 years agoHelpfull: Yes(2) No(7)
• since no 2 women are to be together so choose choose only one women among the three in total we require 7mem. so 6 rom men and 1 women
  
• 9 years agoHelpfull: Yes(1) No(0)
• here we have 4 cases.
  case 1-when no any women is selected --->in this case total selection of 7 members= 12c 7 ....... (1)
  case 2-when 1 woman selected ---> total selection=3 c 1 *12 c 6 ......... (2)
  case 3- when 2 women selected ----> total selection = 3 c2 * 12 c 5 - 6 ......(3) here 6 is the no of ways of selecting 2 girls together
  case 4- when 3 girls taken ...> total selection =3 c 3 * 12 c 4 - 5 -6 .....(4) here 5 is the no of ways of selecting 3 women together nd 6 is the no of ways of selecting 2 women together
  
  FOR 3 GIRLS TOGETHER PLACE THE REMAINING 4 BOYS .NOW WE HAVE 5 SPACE TO FILL B/W BOYS.THESE 5 SPACE CAN BE FILLED BY PLACING 3 GIRLS TOGETHER 5 TIMES. simiarly for 2 women together first we place 5 men then we have 6 space left to fill which can be filled by placing 2 women together 6times
  
  total selection = (1)+ (2)+ (3)+ (4)
• 9 years agoHelpfull: Yes(0) No(3)
• There are 12 men Nd 3 women in which we cannot select two women together so first of all we will select 6men and 1women and then 7men . I.e 12c6*12c1+12c7*12c0
• 7 years agoHelpfull: Yes(0) No(1)
• (12M6 * 3W1 ) + (12M4 * 3W3) = 27422+1045=28067
• 6 years agoHelpfull: Yes(0) No(6)