Find the rank of the word GOOGLE if all the words which can be formed by permuting letters of this word without repitition are arranged in dictionary in alphabetical order???
ans-88

• GOOGLE
  EGGLOO arranging in alphabetiaccal order
  E - - - - - 5!/(2!*2!)=30
  GE- - - - 4!/2!=12 30+12=42
  GG- - - - 4!/2!=12 42+12=54
  GL- - - - 4!/2!=12 54+12=66
  GOE - - - 3!=6 66+6=72
  GOG- - - 3!=6 72+6=78
  GOL- - - 3!=6 78+6=84
  GOOE- - 2!=2 84+2=86
  GOOGE - 1!=1 86+1=87
  GOOGLE 1!=1 87+1=88
  
  So, 88 th no, is GOOGLE
  
  
• 8 years agoHelpfull: Yes(27) No(0)
• https://www.youtube.com/watch?v=n0N3lO3ZI8A
• 8 years agoHelpfull: Yes(8) No(1)
• 5 4 3 2 1 0
  G O O G L E
  now we have to consider the word in alphabetic order,first we are starting from '5'th position that is G,then Find how much letter are there in the right side of G. there is only one letter E and we have seen there are '2' G.So,it will be=1*5!/2!=60
  now considering for O on the same way.the letter of the right side before here we get G,L,E.so it will be=3*4!/2!=36
  after that we don't consider the O,G because it will be repeated.
  now we consider L,here right side letter is E.so it will be=1*1!=1
  for the last digit it will be always 1.
  so the position is 60+36+1+1=88.
  remember: Arrangement is done by using alphabet .Nothing else..
• 8 years agoHelpfull: Yes(3) No(7)
• https://www.youtube.com/watch?v=i3pQZ9I9NJ4
• 8 years agoHelpfull: Yes(1) No(1)
• ans- 441
  youtube search
• 8 years agoHelpfull: Yes(1) No(1)
• 30+36+18+2+1+0+1 = 88
• 7 years agoHelpfull: Yes(0) No(0)