A owe B Rs 250.He agrees to pay B over a number of consecutive days starting from Monday paying single note of Rs 50 or Rs 100 on each day.In how many different ways can A repay B( 2 ways are said to be different if atleast one day a note of different denomination is given)

• 50+50+50+50+50=1 way
  50+50+50+100=4!/3!=4 ways
  50+100+100=3!/2!=3 ways
  
  so, total ways =1+4+3=8 ways
• 8 years agoHelpfull: Yes(20) No(2)
• As 'A' have to pay money in different ways ,means he have to pay at least one different denomiisnation note.
  Hence the way of paying money is as given;
  50,50,50,100= 4!/3!=4 ways.
  100,100,50=3!/2!=3 ways
  A total of 7 ways.
• 8 years agoHelpfull: Yes(7) No(6)
• 50 50 50 50 50--> 1 way
  100 50 50 50--> 4c1=4 ways
  100 100 50--> 3c2 =3 ways
  So, total no. of ways= 1+4+3=8ways
• 8 years agoHelpfull: Yes(3) No(1)
• we have to pay 250 but there is no certain no f days so
  50+50+50+50+50=1 way
  50+50+50+100=4!/3!=4 ways
  50+100+100=3!/2!=3 ways
  
  Total ways =1+4+3=8 ways
• 8 years agoHelpfull: Yes(2) No(1)
• 1. 100+100+50 -- 3 ways
  2. 100+50+50 -- 4 ways
  total= 7 ways
• 8 years agoHelpfull: Yes(1) No(3)
• if B gives 50 per day then form Monday to Friday it pay 50+50+50+50+50=5!/5!=1way
  similarly 50+50+50+100 then 4!/3!=4ways
  50+100+100 is next possible way=3!/2!=3ways
  finally 1+4+3=8ways
• 8 years agoHelpfull: Yes(1) No(0)
• eqn formed 50x +100y = 250
  putting y=0,x=5... 1 ways
  putting y=1,x=3....4! ways
  putting y=2,x=1...3! ways
  
  hence total ways= 1+4!+! = 31 ways Ans
• 8 years agoHelpfull: Yes(0) No(11)