Sixty men complete a work in 25 days. One man starts working it at and thereafter one more man joins him every day. In how many
days the work will be completed?

• 1 mens 1 day work =1/1500
  1/1500(1+2+3+........n)=1(as total work=1)
  We need to find n it cannot be greater than 60
  Here the answer is 55(approx)
• 8 years agoHelpfull: Yes(18) No(2)
• Ans is 54 3/11 days.
  becoz, for one men it takes (1/1500)days and so on..
  n(n+1)/2=1500 ...soln is approved..
• 7 years agoHelpfull: Yes(10) No(0)
• let one man can do 1 unit work in one day
  total unit work is=25*60;
  so 1+2+3................+n=25*60;
  n=110
  ans=110
• 8 years agoHelpfull: Yes(7) No(21)
• let one man can do 1 unit work in one day
  total unit work is=25*60;
  so 1+2+3................+n=25*60;
  n=54.275
  ans=54.275
• 7 years agoHelpfull: Yes(3) No(0)
• Ans :80
  (1+2+3+.......n)/60*25=60/25 by solving we get 80
• 8 years agoHelpfull: Yes(2) No(5)
• One man work =1/(25*60)
  
  work is done by two men hence= 2/(25*60)
  
  Both of them finish in 750 days.
  
  
• 8 years agoHelpfull: Yes(2) No(11)
• 2^2 other numbers are prime numbers
  
• 8 years agoHelpfull: Yes(1) No(17)
• first calculate one man work
  60 man 1 day work is= 1/25
  1 man 1 day work is =1/25*60
  now acc to problem series become
  1/25*60+2/25*60+3/25*60..................=1
  1/1500(1+2+3+.........)=1
  sum of A.P is
  1/1500(n/2 [n+1])=1
  on solving this we get n is not grater than 60 hence 55 approx is corecct
• 4 years agoHelpfull: Yes(0) No(0)