TCS
Company
Numerical Ability
Permutation and Combination
In a question paper, there are 4 MCQ's having 5 options each. in how many ways candidate will not get all four correct answers?
a)624 b)625 c)623 d)none of these
Read Solution (Total 4)
-
- total possible ways =5^4 =625
no of ways in which all q get correct answer =1
therefore , No of ways candidate will not get all four correct ans = 625-1=624 - 9 years agoHelpfull: Yes(34) No(0)
- 5c4 is the number of way a person correct answer in 1st question.
So foe 4question 5c4 * 5c4 * 5c4 * 5c4= 625 - 9 years agoHelpfull: Yes(1) No(8)
- every ques can be ans in 5 way so there is total 5*5*5*5 way of ans a question but total way of giving a correct ans is 1so no of way in which he can give the wrong ans is 625-1=624
- 9 years agoHelpfull: Yes(1) No(0)
- A candidate can answer the test in 5*5*5*5=54 number of ways (each question has 5 choices and we have total of 4 questions).
Now, out of these cases there will be only one case when the candidate answered all the four questions correct.
Therefore the total number of ways in which a candidate will not get all the four answers correct is 54-1=624. - 3 years agoHelpfull: Yes(0) No(0)
TCS Other Question