Ten years ago, A was half of B in age. If the ratio of their present ages in 3 : 4, what will be the total of their present ages?
A. 15 yrs
B. 20 yrs
C. 35 yrs
D. 40 yrs

• let present age of A and B is 3x:4x respectively
  (3x-10)*2/(4x-10) give x= 5
  so x age is 15 year and y age is 20 yrs
  x+y = 35
• 9 years agoHelpfull: Yes(4) No(0)
• A : B
  x : 2x
  
  After 10 years their age is= x+10/2x+10=3/4
  x=5
  their total age is= 3x= 15
• 9 years agoHelpfull: Yes(3) No(5)
• 10 year ago,
  A= x year
  B= 2x year
  after 10 year,
  (x+10)/(2x+10)=3/4
  x=5
  A= 5 , 10 year ago,
  B=10, 10 year ago
  present ages, 15 and 20
  sum= 35
• 9 years agoHelpfull: Yes(2) No(0)
• A:B=3x:4x
  10 years ago age of A=3x-10
  10 years ago age of B=4x-10
  
  from question,
  2 *(3x-10)=4x-10
  6x-20=4x-10
  6x-4x=-10+20
  2x=10
  x=5
  
  then present age of A=3x=3*5=15
  present age of B=4x=4*5=20
  
  total of their present ages=15+20=35
  
• 9 years agoHelpfull: Yes(1) No(0)
• According to karishma A was "minus five year" old ten years ago
• 9 years agoHelpfull: Yes(0) No(0)
• present ages a,b
  10years ago a-10,b-10
  
  a-10=1/2(b-10) => 2a-b=10 -----------(1)
  now a/b=3/4 => 4a=3b => a=3b/4---------(2)
  
  replacing (2) in (1)
  2*3b/4-b=10 => b=20 then a=15
  
  so a+b= 35
• 7 years agoHelpfull: Yes(0) No(0)