An electric wire runs for 1 km b/w some no: of poles. If one pole is removed the distance b/w each pole increases by 1 2/6 (mixed fraction). How many poles were
there initially?

• let no. of poles = n and the distance b/w each pole is x;
  ==> n * x= 1;--------------1
  now 1 pole is removed ==> n-1;
  Distance inc ==> 7x/3;
  ==> (n-1)*7x/3=1----------------------2
  from 1 and 2
  n=4 ==> no. of poles =n-1=3 ans(3)
• 8 years agoHelpfull: Yes(15) No(21)
• let there be x no. of poles
  distance b/w them= 1/(x-1)
  now when one pole is removed
  distance bw each pole=1/(x-2)
  now according to the question
  1/(x-2) =8/6 (1/x-1)
  on solving you will get x=5
• 8 years agoHelpfull: Yes(13) No(2)
• let we have n poles...and dist b/w two poles is x.
  then..
  length of wire,
  (n-1)*x=1....equ1
  if one pole is removed then,
  (n-2)*(4x/3)=1...equ2
  solve this two equations.....n=5.
• 8 years agoHelpfull: Yes(4) No(0)
• ans 5
  let the no of pole and distance b/w pole be n,x respectively
  acc to first condition of question n*x=1...........(a)
  acc to second condition (n-1)*((8*x)/6)...............(b)
  solving eqn a ,b we get x=1/4 which means no of pole be 5.
• 8 years agoHelpfull: Yes(3) No(1)
• Let no. of poles=n & the distance between each pole is x
  (n-1)*x=1 km wire......(i)
  Now 1 pole is removed and distance increased by 4/3
  i.e. new distance = x+4x/3 = 7x/3
  (n-2)* 7x/3 = 1 Km wire.............(ii)
  From (i) & (ii)
  n~=4 (No. of poles initially)
  
  
• 8 years agoHelpfull: Yes(2) No(1)
• if it is increased to 4/3 then no. of poles =5
  if it is increased by 4/3 then no. of poles= fractional values we will get
• 5 years agoHelpfull: Yes(1) No(0)
• please provide right soln fo this
  
• 8 years agoHelpfull: Yes(0) No(2)
• 6 is right answer
• 8 years agoHelpfull: Yes(0) No(2)
• let there be n no. of poles
  distance b/w them= 1/(n-1)
  now when one pole is removed
  distance bw each pole=1/(n-2)
  according to the question
  1/(n-2) =8/6 (1/n-1)
  on solving you will get x=5
• 7 years agoHelpfull: Yes(0) No(0)
• 5 is the
  n is no of poles
  n-1 is the no of
  so (n-1)+x=1-----(1)
  1pole is removed and the distance is increased by 8/6
  (n-2)+8/6x=1----(2)
  On dividing (1)/(2) we
  3 (n-1)=4 (n-2)
  On solving we get n=5
• 6 years agoHelpfull: Yes(0) No(1)
• Kalil zebran: answer:n=3
• 6 years agoHelpfull: Yes(0) No(1)