Elitmus
Exam
Logical Reasoning
Cryptography
G A E
*M R A
-------------
XBRX
ABKS*
BRPR**
------------
GXGXPX
Read Solution (Total 5)
-
- 643
*974
--------
2572
4501
5787
--------------
626282
- 9 years agoHelpfull: Yes(4) No(2)
- Frst we try to find out d value of x as it is vry reptve
GAE
A
-----------
XBRX
From dis we can conclude dat smallest value to dis is either 1 or 2 it may be more bt try frst for x=1 n 2
So we find aftr slvng dat
X=2
N G=6
A=4 E=3 R=7 B=5
Den GAE
R
-----------
We get S=1 n K=0
Den
GAE
M
---------
We get P=8 n M=9
- 9 years agoHelpfull: Yes(2) No(0)
- In the above problem, we are able to find only one conclusion in first look that is 1+B=G;
Now we just try hit and try method;
first of all we put E=2 not 1 coz anything multiply by 1 gives the same value and values are vary here, try to find out all possible values of A that may be 3,4,5,6,7,8,9
As if we put A=3
than X=6, and R=9; S=8, K=8 that can't be possible.
G32
M93
-------
6B96
88*
So go on...
you can figure out that E=2 is not a possible value.
Now put E=3, A=2;
Than X=6, R=4, S=2 that can't be possible.
G23
M42
-------
6B46
2*
Now, let us put E=3, A=4;
Than X=2, R=7,S=1,K=0,M=9,P=8,G=6;
643
974
-------
2572
4501*
5787**
-----------
626282 - 9 years agoHelpfull: Yes(1) No(0)
- Try with GAE*A=XBRX so vl get X as 2
643
974
---------
2572
4501-
5787--
-----------
626282 - 9 years agoHelpfull: Yes(0) No(0)
- 643
974
____
2572
4501
5787
______
626282 - 9 years agoHelpfull: Yes(0) No(0)
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