H M K
* A V E
------------------------
A N X X
X AV H
M X V W
------------------
M A M V W X

• First we will see that which alphabets can be 0 or not.
  (A,X,V,H,M,K,E)!=0 ; (W & N )=0,
  Now , N can't be 0 bcoz E*K=X and E*M=X can't be possible it will definitely gives a carry. so N can't be 0 after adding something .
  So, W==0.
  Now, In the equation K*A=W, either K or A should be 5 to make W=0;
  If we take K as 5 then in all the equation K*E ,and K* V always there will be 5 and 0 will be the result which is not possible.
  So, A will be 5 for sure. And K will be 2,4,6 or 8.
  As we can see that M=M in the last so X+X+A will not give any carry and A is 5. It can be only possible when X will be 2 so that the equation will be 2+2+carry(1) will be 5.
  Now for the equation K*E=X; We will put 4 bcoz K now will be only 4,6 & 8.
  So the equation will be 4*3=12 to make X =2. But it will not suite the whole equation multiple with because it will not give M a correct value so that X will come 2.
  Now we will take K =6.
  Now. the equation will be 6*7=42. The next equation M*E+carry=X as (4*7+4=32)
  and the next equation H*E+carry=AN will be(8*7+3=59).
  Now start putting all the values . The remaining alphabets will be clearly come out with an another value.
  
  So our result be like as
  
  8 4 6
  *5 3 7
  -------------------
  5 9 2 2
  2 5 3 8
  4 2 3 0
  ------------------
  4 5 4 3 0 2
  
  
• 8 years agoHelpfull: Yes(17) No(1)
• 846
  *537
  --------
  5922
  2538
  4230
  --------------
  454302
  
• 8 years agoHelpfull: Yes(4) No(3)
• Just look the Double X in the equation ok
  
  H M K
  * A V E
  ------------------------
  A N X X
  X AV H
  M X V W
  ------------------
  M A M V W X
  
  
  first write it as
  
  H M K
  * E
  ---------------
  A N X X
  
  
  just start substuting the values of X .. Start with 1 ok so to make X =1 we have to take E=7 and k =3 so we have 7(E)*3(k)=21 .2 will be carry and we have X=1 . Now we have one more X so we have the value of E=7 and we have to multiply with M so we can find a value that ends with 1 after adding the 2 (Carry from E*K=21). But if u go all the values from 0-9 you don't find any value for it.
  
  so nw we will take X=2 .To make X=2 we take the value of E=2 and K=6 we get 2(E)*6(k)=12 we get X=2 but condition fails as we have E=2 we can't have the two alphabets with the same number .
  
  after you go through some value u will find for E=7 and K=6 we get 42 ... 2 as the X and 4 carry .Now to make E*M =X we take M=4 .. then we will get E(7)*M(4)+ carry(4)=32 so X=2 and 3 will be carry.
  
  nw replace all the X in the equation by 2.
  
  
  H 4 6
  * A V 7
  ------------------------
  A N 2 2
  2 AV H
  M 2 V W
  ------------------
  4 A 4 V W 2
  
  we can see by adding 2+2=A(4)... but it cannot be 4 as we have M=4 .So there must be carry from previous addition.So lets tale A=5.Now start as
  
  H 4 6
  *5 V 7
  ---------------------
  4 2 V W
  
  Now 5(V)*6(k)=30.... W=0 and 3 will be carry now 5(A)*4(M)+carry=23 ..V=3 and 2 will be carry and then 5(A)*H=42 ... so the 8 will be the right value to get 42.
  
  Now you can take down all the values .
  
  
  
  
  
• 8 years agoHelpfull: Yes(4) No(0)
• first of all split the question in three part
  1) HMK
  * E
  ------------
  ANXX
  ---------
  2) HMK
  * V
  ----------
  XAVH
  ----------
  3) HMK
  *A
  -----------
  MXVW
  -----------
  from part 1 result xx(check as 11,22,33,44)
  if you think 11 then possible value for that is (3*7) or (7*3)
  for 22 possible values are (2*6) ,(6*2),(4*3),(3*4),(8*4),(4*8),(7*6),(6*7)
  take value for K=6 and E=7
  so ,
  846
  *537
  -----------
  5922
  2538
  4230
  -----------
  454302
  ----------
• 8 years agoHelpfull: Yes(1) No(0)
• 846
  *537
  ---------
  5922
  2538
  4230
  -----------
  454302
  
  
  
• 8 years agoHelpfull: Yes(0) No(0)
• 846
  537
  ______
  5922
  2538
  4230
  ______
  454302
• 8 years agoHelpfull: Yes(0) No(0)