Three variables x,y,z have sum of 30.All three of them are non-negetive integers.If any two variables don't have same value and extacly one variable has a value less han or equal to three,then find the number of possible solution for variables.

• let digits be X,Y,Z
  X Y Z
  0 (1 ,29),(2,28),(3,27) ............(29,1) no of possibilities=29
  1 (0,29),(2,27),(3,26).............(27,2),(29,0) no of possibilities=28
  2 (0,28),(1,27),(3,25).............(25,3),(27,1),(28,0) no of possibilities=27
  3 (0,27),(1,26),(2,25),(4,23)...........(23,4),(25,2),(26,1),(27,0) no of possibilities=26
  total no of possible solutions are 29+28+27+26=110 possibilities
• 9 years agoHelpfull: Yes(17) No(11)
• A= 3 there is 20possiblities of selecting different numbers of b and c
  A= 2 , -----------------------20possiblities
  A=1 ____________ 22posiblities
  A=0 again 22posiblities so answer is 20+ 20+ 22+ 22= 84
• 9 years agoHelpfull: Yes(5) No(10)
• solution 2 must be modified.
  The number of ways of selecting exactly one variable having value less than or equal to 3 is 3.
  So the number of solution is=3*84=252
• 9 years agoHelpfull: Yes(1) No(3)
• let x,y,z are the digits
  z has 4 possibilities i.e., z=0,1,2,3
  so wen z=0 there are 28 possibilities
  when z=1 there are 26 possibilities
  when z=2 there are 22 possibilities
  when z=3 there are 20
  so total 96
• 9 years agoHelpfull: Yes(0) No(4)
• which one is correct plzzztell me?//
• 9 years agoHelpfull: Yes(0) No(3)
• Which one is correct answer
• 9 years agoHelpfull: Yes(0) No(1)
• Ans is 56 .... let the digis are x, y ,z
  then if we ll take 0 ,1,2,3 as one variable then there are 14 posibilties in each 4 case then the total no possibilties are 56
  
• 9 years agoHelpfull: Yes(0) No(1)
• asnwer is 294 ..... and other solved answers below are wrong
• 9 years agoHelpfull: Yes(0) No(3)
• @prashanthi.. the three values can be hold by any of the three variables.. not necessery in the sequence of X Y Z.. they cab be arranged themselves in 3! ways.. so the final answer is -- 110X3!=660...
• 8 years agoHelpfull: Yes(0) No(4)