A play school has chocolates which can supply 50 students for 30 days. For the first ten days only 20 students were present. How many more students can be accommodated into the earlier group such that the entire chocolates get consumed in 30 days. Assume each student takes the same number of chocolates

• total no.of chocolates=30*50=1500
  as for ten days only 20 students were present so chocolates given=20*10=200
  remaining chocolates=1500-200=1300
  chocolate given in next 20 days=1300/2=65
  as 20 students are already there so no of students=65-20=45
  so ans=45
• 8 years agoHelpfull: Yes(40) No(3)
• 15 more students
• 8 years agoHelpfull: Yes(16) No(8)
• Let each students gets 1 chocolate. Now total chocolates = 50 x 30 = 1500
  If first 10 days only 20 students were present, then total chocolates consumed = 10 × 20 = 200
  Now we are left with 1500 - 200 = 1300 chololates. These were to be consumed in 20 days.
  So each day 1300/20 = 65 chocolates were to be distributed.
  So we can add 65 - 20 = 45 students
• 8 years agoHelpfull: Yes(6) No(0)
• 65-20-30=15 so 15 more student are needed
• 8 years agoHelpfull: Yes(5) No(3)
• let us consider chocolate consumed by each student is 1. Therefore total no of chocolate required for 50 students for 30 days is 1500.
  for first 10 days only 20 students are present, so chocolates consumed is 10*20 = 200.
  for remaining 20 days let us consider all 50 students are present the so chocolates consumed is 20*50= 1000.
  for this case 1000+200=1200
  remaining chocolates are 1500-1200 = 300
  so for the first 10days 10 * x(i.e.,student) = 300
  x=30 students can be added to the ten days.
• 8 years agoHelpfull: Yes(5) No(4)
• i'm confusing with these answer. is that 45 or 15 ?
• 8 years agoHelpfull: Yes(5) No(2)
• total num of chocolates =30*50=1500
  for the first ten days only 20 students were present so assume 20 students get 2 chocolates per day so the remainind chocolates were 1500-400=1100
  apart from this 20 students the 1100 chocolates can be given to 55 students for 20 days so that each student gets 1 chocolate a day
  so over all each student receives 20 chocolates
  so 55 students can be accomodated
  
• 8 years agoHelpfull: Yes(4) No(7)
• no of student days =50*30
  amount consumed =20*10
  so
  50*30=20*10 +(20+x)*20
  x=45
• 8 years agoHelpfull: Yes(4) No(0)
• 50x30=1500 chocloates- 30 days-50 students
  1 student-30choc
  20 students-20x30=600chc are distributed in first 10 days
  remaining 1500-600= 900 choc should be distributed in 20 days
  20*x=900=>x=45
  ans 45 students
  
• 8 years agoHelpfull: Yes(3) No(0)
• let the no of accommodated students is x.
  so
  from the equation
  (20 + x)* 30+ 20*10 =1500
  solve this equation
  and get the value of X
• 8 years agoHelpfull: Yes(1) No(4)
• Why don't you compare with time and work problems? :D
  50*30 = 10 days*20 students+20 days*S students .
  By solving s= 65,
  =>new students accomadated = 65-20= 45.
• 8 years agoHelpfull: Yes(1) No(1)
• 10 more students
• 8 years agoHelpfull: Yes(0) No(5)
• 20 students
• 8 years agoHelpfull: Yes(0) No(4)
• 20 students
• 8 years agoHelpfull: Yes(0) No(4)
• first we seehow much chocolates have after 10 days it is 1- (10*20)/(30*50)=13/15
  then left 20 days so total students =(50*30*13)/(20*15)=65
  so ans 65-50=15
• 7 years agoHelpfull: Yes(0) No(1)
• 15 students
• 4 years agoHelpfull: Yes(0) No(1)
• total no.of chocolates=30*50=1500
  as for ten days only 20 students were present so chocolates given=20*10=200
  remaining chocolates=1500-200=1300
  chocolate given in next 20 days=1300/2=65
  as 20 students are already there so no of students=65-20=45
  so ans=45
• 4 years agoHelpfull: Yes(0) No(0)