Train A travels from X to Y at 5km/h &Train B travels Y to X at the speed of 7km/h respectively.distance between x and y is 27km.After how much time they will meet at mid point of X and Y ?

• Actually question was when they will meet at the middle of the station at the second point.They will reverse their direction each time they will reach the other station.
  
  U can check each option one by one to get the answer.The first option was 40.5.
  
  After 40.5 hr A will cover 202.5km. ( 27+27+27+27+27+27+27+13.5) or (27*7=189+13.5)At this moment A is in the middle of both station.
  
  After 40.5 hr B will cover 283.5 km.(27+27+27+27+27+27+27+27+27+27+13.5) or (27*10+13.5).At this moment B is also in the middle of both station.
  
  This concludes that A & B are standing at 13.5 km from both station(i.e middle of both station) after 40.5 hrs.
• 9 years agoHelpfull: Yes(27) No(3)
• Ans will be 2 hrs 15 min
  
  lets first train A goes to point from X to Y--> 2 hrs then it covers-->10 km
  at the same time train B goes to point from Y to X-->2 hrs then it covers--> 14 km
  so total distance has been covered-->24 km
  
  remaining 3 km
  
  train A covers the distance in 1 min-->5/60=1/12 km
  so it covers the distance in 15 min-->(1/12)*15-->5/4 km
  
  and train B covers the distance in 1 min-->7/60 km
  so it covers the distance in 15 min-->7/4 km
  
  so total distance will be 5/4+7/4-->3 km
  
  so they will meet after 2 hrs and 15 min
• 9 years agoHelpfull: Yes(11) No(6)
• please admin u should upload correct answer or answer option also..we are getting confuse after reading many answers
• 8 years agoHelpfull: Yes(10) No(0)
• two train in opposite direction so their speed=5+7=12 km/h
  so time=27/12 =2.25h
• 9 years agoHelpfull: Yes(4) No(11)
• Ans is 40.5
• 9 years agoHelpfull: Yes(2) No(3)
• Let there is a point A in the etween where they met.
  So time taken by both of them is equal to reach there.
  xa/5 = ya/7
  xa+ ya = 27.
  xa=27-ya
  Putting the above equation in the first written equation we got ya = 63/4.
  
  Put ya in ya/7 for time taken to meet them.
• 9 years agoHelpfull: Yes(0) No(4)
• mid point distance=7-5=2
  so ,27/2=13.5 is the ans
• 9 years agoHelpfull: Yes(0) No(8)
• since they are meeting at midpoint...so tym taken by slowest person-2hr 42min.
  
• 9 years agoHelpfull: Yes(0) No(0)
• After 2hr 15 they will meet at mid point
• 9 years agoHelpfull: Yes(0) No(1)
• since we know average speed is given by =2.5.7/7
  avrg speed=total distance/total time
  s directly proprtional to 1/t
  solve these eqn got answer 2hrs.08 mints
  
• 9 years agoHelpfull: Yes(0) No(0)
• where r the options
• 9 years agoHelpfull: Yes(0) No(0)
• Time is constant (27/2)n1/5=(27/2)n2/7 so that n1/n2=5/7 it means first train complete 5 round of 27/2 and second train also complete 7 round 27/2 distance and both stand at middle
  now time equal to (27/2 + 27/2 + 27/2 + 27/2 + 27/2 )/5 equal to 27/2 hours
  
• 8 years agoHelpfull: Yes(0) No(0)
• The correct question is:
  A and B walk from X to Y, a distance of 27 km at 5 kmph and 7 kmph respectively. B reaches Y and immediately turns back meeting A at Z. What is the distance from X to Z?
• 7 years agoHelpfull: Yes(0) No(0)
• Admin is sleeping all the time, that's why this wronge question has been published. If not then this my comment will also not permitted.
• 2 years agoHelpfull: Yes(0) No(0)