Elitmus
Exam
Numerical Ability
Probability
Probability of Cristiano Ronaldo scoring a penalty is twice than the probability of missing it. In a World cup he takes 5 penalties, What is the probability of scoring 3 penalties among the 5?
Option:
a) 5*2*((2/3)^3 * (1/3)^3)
b) 1-((2/3)^3 * (1/3)^3)
c) 1-((2/3)^2)
Read Solution (Total 4)
-
- P+2P=1
now p=1/3;
so answer is 5c3*(2/3)^3(1/3)^2 - 9 years agoHelpfull: Yes(28) No(1)
- Sorry.....
Options are:
a) 5 *2 *((2/3)^3 * (1/3)^2)
b) 1-((2/3)^3 * (1/3)^2)
c) 1-((2/3)^2 * (1/3)^3) - 9 years agoHelpfull: Yes(3) No(0)
- P(s)=2/3, P(m)=1/3
The probability of scoring 3 = 5c3*(2/3)^3*(1/3)^2
=5*2*((2/3)^3*(1/3)^2) - 9 years agoHelpfull: Yes(3) No(0)
- x+(x+1)+(x+2)+(x+3) == 4x+6 = y
y is multiple of 10 only when x's units place is either 1 or 6
1+2+3+4 and 6+7+8+9
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991+992+993+994 and 996+997+998+999
as per the permutations formula
1digit , 2 digit , 3digit numbers are
= 2 + ( 9*2 ) + ( 9 *10 * 2 ) == 200
- 9 years agoHelpfull: Yes(0) No(3)
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