Maths olympiad
Exam
General Ability
who are the 3 digit numbers that sum 18 and are divisible by 13 and 4
Read Solution (Total 3)
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- 468, 936
Numbers divisible by 13 and 4 will be N*(13*4)=52, 104, 156, 208, 260,.........,988
Out of these 3 digit numbers 468 and 936 will have sum=18 - 8 years agoHelpfull: Yes(1) No(0)
- clearly,the required number has to end with atleast 6,2 ,8,4 or 0.So we start multiplying 13 with 22,24,26,28,30,32,34,36.On multiplying 13 with 36,we get 468 which is divisible by 4.Hence,468 is our required solution.
- 8 years agoHelpfull: Yes(0) No(0)
- 13X4=52
Multiple of 52..... 3 digit number with digit sum is 52X9=468
- 8 years agoHelpfull: Yes(0) No(0)
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