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tee+let=All where E=5 find A+L+L
Read Solution (Total 19)
-
- T E E
+ L E T
= A L L
SO, suppose E=5 and L =6, then L=1(carry 1),
again E +E i.e 5+5+(carry 1)=1, again (carry 1);
earlier we have taken T=6 and after summation L= 1
so, T+L=6+1+(carry 1)=8
so, A=8, L=1
A+L+L=8+1+1=10 - 9 years agoHelpfull: Yes(16) No(1)
- T=6,L=1,A+L+L=10
- 9 years agoHelpfull: Yes(4) No(1)
- answer is 10... here a is not 1 ,0 and 5... so put choice in t from 1 to 9 except 5...noe chooesn value of t is 6 now 5+6=11 value of l=1 so we can say e=5,l=1, t=6,a=8
- 9 years agoHelpfull: Yes(3) No(0)
- Answer:10
As Given that,E=5
we should give some number to T such that ,both the values of L in the result is equal
T 5 5
L 5 T
A L L
clearly 5+5=10,but we can't say that L is 0,there may be a carry hailing from 5+T
BY trial and Error,If suppose T=6,then L=_1,where 1 is the carry and 1+5+5=_1
therefore,L=1 and T=6 and
655+156=811
therefore,A=8 - 9 years agoHelpfull: Yes(3) No(3)
- 655
+156
--------
811
-------- - 9 years agoHelpfull: Yes(2) No(0)
- TEE+ LET=ALL. E=5.
T55+L5T=ALL.
From above equation, 5+T=11[E+E=E+T=L].So, T=6,L=1 AND A=8.
A+L+L+=8+1+1=10.
ANSWER =10 - 9 years agoHelpfull: Yes(1) No(1)
- T E E
+LET
-------------
A L L
A=8
E=5
T=6
L=1
- 9 years agoHelpfull: Yes(1) No(0)
- T55
L5T
----
ALL
-----
=>L=10 OR 11(IF CARRY PRODUCED FROM 1ST COLUMN) eq1
=>5+T=L OR 5+T=10+L eq2
from eq1 and eq2 clearly L should be either 0,1 for this but however from E+T=L CARRY will be produced bcz if L wants to be 0 or 1 T should be 5 or 6 from this only T=6 satisfies eq1 and eq2 so L=1
so A=T+L+carry1=>8
L=1
so A+L+L=8+1+1=10 - 9 years agoHelpfull: Yes(1) No(0)
- T E E
+ L E T
= A L L
SO, suppose E=5 and L =6, then L=1(carry 1),
again E +E i.e 5+5+(carry 1)=1, again (carry 1);
earlier we have taken T=6 and after summation L= 1
so, T+L=6+1+(carry 1)=8
so, A=8, L=1
A+L+L=8+1+1=10
- 9 years agoHelpfull: Yes(1) No(0)
- T E E
+L E T
=let l=1 it may be a cary 1 or 11 and e=5 so t=6 5+6=1 with cary 1 then E+E +1(cary )=1 then T=6 ,T+ 1+1=8
a=8,l=1
A+L+L=8+1+1=10 - 8 years agoHelpfull: Yes(1) No(0)
- 655
+156
______
711 - 8 years agoHelpfull: Yes(1) No(2)
- t e e t 5 5 [ 5+ 5=l,,,,,,5+t=l here to satisfy these two conditions t must be 6 which implies
l e t l 5 t l=1]
------- ----------
a l l a 11 [now a=t+l+1(carry from 5+5+l),,,,i.e a=6+1+1=8..................a+l+l =8+1+1=10 - 8 years agoHelpfull: Yes(1) No(0)
- firstly we have E=5 then arrange our question
T 5 5
L 5 T
-----------
A L L
let start with T
t 's value will bhi 6,7,8
so web taken firstly 6
6 5 5
1 5 6
-----------
8 1 1 - 6 years agoHelpfull: Yes(1) No(0)
- t=6
l=1
a=8
ANS:10 - 6 years agoHelpfull: Yes(1) No(0)
- If E=5 then A=1,L=12 then 1+12+12=25
- 9 years agoHelpfull: Yes(0) No(2)
- A=7,E=5,T=6,L=1
All=9 - 8 years agoHelpfull: Yes(0) No(2)
- T e e=6 5 5
+ L E t=1 5 5
=A l l =8 1 1
A +l +l=10 - 6 years agoHelpfull: Yes(0) No(0)
- 11
655
+256
=911 - 6 years agoHelpfull: Yes(0) No(0)
- tee=655
let=156
all=811 - 6 years agoHelpfull: Yes(0) No(0)
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