Two friends running up hill and get down. length of road is 440 yards. A on his return journey met B going up at 20yards from top. If A has finished 5 minutes earlier than B. Then how much time A has taken to complete the race

6.2
6.5
6.4
6.3

• ans is 6.3
• 8 years agoHelpfull: Yes(8) No(13)
• When A travels 460m (=440+20),
  
  B travels 420m (=440-20). So, ratio of speed = 460:420
  
  = 23:21.
  
  Let A's speed be 23x, and that of B's be 21x.
  
  => 23x = ((2 * 440) / t) which implies 23t = 880/x;
  
  => 21x = ((2 * 440) / (t+5)) which implies 21(t+5) = 880/x.
  
  From these two equations, 23t = 21(t+5). Solving, t = 52.5
• 8 years agoHelpfull: Yes(7) No(0)
• A .
  gains 20 yards over B in it's down the hill journey.
  So for entire journey A will have a lead of 40 yards over
  B.
  now, when A is at destination B is 40 yards behind which B will cover in 5 minutes.
  so, by unitary method we get..
  For B,
  40 yards in 5 minutes
  therefore,1 yard in 5/40 minutes
  therefore,880 yards in (5/40)*880=110 minutes.
  Now b takes 110 minutes
  so
  A will take 105 minutes.
  
• 8 years agoHelpfull: Yes(3) No(5)
• PLZ tell me when will be the recruitment drive of L&T?
• 8 years agoHelpfull: Yes(2) No(2)
• @akansha how??
  
• 8 years agoHelpfull: Yes(0) No(5)
• otal journey= 440 × 2=880
  
  A meet B 20 yards from top in getting down it means he has covered 440+20=460 yards while B is 420 yards.so he is 40 yards ahead of B which is equals to 5 minute.
  
  so 40 yards in 5 min
  
  880 yards will be in 5 × 880/ (40) =110 minute.
• 5 years agoHelpfull: Yes(0) No(0)