How many ways can 1500 be expressed as a product of three numbers

• HCF OF 1500= 2^2*3*5^3
  THEREFORE AS WE KNOW WHEN N=A^P*B^Q*C^R FOR PRODUCT OF 3 NUMBERS
  IS EXPRESSED AS 1/2[(P+1)(Q+1)(R+1)]
  SO HERE THE ANSWER IS 1/2 *24 = 12
• 8 years agoHelpfull: Yes(14) No(8)
• 7p3=7!/4!=210
• 8 years agoHelpfull: Yes(7) No(9)
• 1500=2*3*5*5*5*2
  so by combining
  combo1=(2*3)*(5*5)*(5*2)=1500
  combo 2=(2*2)*(3*5)*(5*5)
  combo3=(5*3)*(5*2)*(5*2)
  ans.3
• 7 years agoHelpfull: Yes(3) No(2)
• 1500=25*20*3
• 9 years agoHelpfull: Yes(0) No(14)
• Express 3240 as a factors of prime nos
  
  3240 = 2 x 2 x 2 x 3 x 3 x 3 x 3 x 5 = 23 x 34 x 5
  
  so these 3 nos of 2's can be distributed to 3 integres a,b,c in : [3+(3-1)]C (3-1) ways i.e 5C2 = 10 ways
  
  Nos of ways in which 4 nos of 3's can be distributed to 3 integers : [4+(3-1)]C (3-1) ways i.e 6C2 = 15 ways
  
  Nos of ways in which 1 nos of 5 can be distributed to 3 integers : [1+(3-1)]C (3-1) ways i.e 3C2 = 3 ways
  
  So total ways = 10 x 15 x 3 = 450
• 8 years agoHelpfull: Yes(0) No(1)