include void fun int p int q 10 p q int main void int r 20 int p r fun

it will return the value of r that means 20. bcoz void fun doesn't return any value.
8 years agoHelpfull: Yes(1) No(0)

The answer is 20 because in fun() , the variable p is a local pointer variable of another stack and having another address. So is stores the address of q. But it is not returning anything. So the pointer variable p of main stack is still holding the address of r.
8 years agoHelpfull: Yes(1) No(0)
ans is 20 because there is call by value so there will be no change in the main()
8 years agoHelpfull: Yes(0) No(0)
it is passing value as parameter not reference of r
so ans should be 20
8 years agoHelpfull: Yes(0) No(0)
20
#include
void fun(int *p)
{
int q=10;
p=&q;
}
int main(void) {
int r=20;
int *p=&r;
fun(p);
printf("%d",*p);
return 0;
}
7 years agoHelpfull: Yes(0) No(0)
It firstly point to the r but in main it starts point to the q thus it returns 10 .. Due to call by pointer
4 years agoHelpfull: Yes(0) No(0)

#include
void fun(int p)
{
int q=10;
p=&q;
}
int main(void) {
int r=20;
int p=&r;
fun(p);
printf("%d",*p);
return 0;
}