log xy 3 a log x 2y b then value of log y log x

logx+3logy=a........(1)
2logx+logy=b........(2)
multiply eqn (1) by 2 & rewrite
2logx+6logy= 2a.......(3)
2logx+logy=b...........(4)
3-4
5logy=2a-b
logy=2a-b/5..........
put the value of log y in any equation & find logx
2logx+2a-b/5=b
logx=3b-a/5.......
logy/logx=2a-b/5 *5/3b-a
=2a-b/3b-a.....
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8 years agoHelpfull: Yes(2) No(1)
log xy^3=a
log x+log y^3=a
log x+3log y=a------(1)
log x^2y=b
2log x+log y=b-------(2)
solve by equ (1) and (2)
log x= (2b-a)/5
log y= (2a-b)/5
log y /log x=(2a-b)/(2b-a)
8 years agoHelpfull: Yes(1) No(3)
Simi you are right I also got the same answer
8 years agoHelpfull: Yes(0) No(1)
logx+3logy=loga
2logx+logy=logb
5logy=log(a^2/b)
5logx=log(b^3/a)
logy/logx=log(a^2/b) / log(b^3/a)
8 years agoHelpfull: Yes(0) No(1)

log xy^3=a
log x^2y=b
then value of log y /log x