A bartender stole champagne from a bottle that contained 50% of spirit and the he replaced what he had stolen with champagne having 20% spirit. The bottle then contained only 25% spirit. How much of the bottle did he steal? P.S. plz provide explanation!

1) 80%
2) 88.88%
3) 83.33
4) 85.71

• Considering the situation as mixing 20% spirit into 50% spirit making 25% spirit champagne This is a alligation problem
  so, 20 25 50
  25 5
  5 1
  So, mixed in the ratio of 5:1 means bartender mixed 20% spirit into original 50% spirit in the ratio of 5:1 Means 5/6 of the bottle is stoled by bartender which is 5/6*100 = 83.33%
• 9 years agoHelpfull: Yes(4) No(2)
• 1 bottle is contained 50% of spirit , stolen by bartender and replaced having 20% spirit. Finally Bottle is contained 25% spirit.
  Cheaper(c) quantity 20%
  Dearer(d) Quantity 50%
  Desire (m) Quantity 25%
  d-m:m-c
  25:5
  5:1
  
  bottle steal quantity 5/6
  Percentage
  5/6*100=83.33%
  Ans 83.33%
• 5 years agoHelpfull: Yes(3) No(0)