MBA
Exam
A bartender stole champagne from a bottle that contained 50% of spirit and the he replaced what he had stolen with champagne having 20% spirit. The bottle then contained only 25% spirit. How much of the bottle did he steal? P.S. plz provide explanation! 1) 80% 2) 88.88% 3) 83.33 4) 85.71
Read Solution (Total 2)
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- Considering the situation as mixing 20% spirit into 50% spirit making 25% spirit champagne This is a alligation problem
so, 20 25 50
25 5
5 1
So, mixed in the ratio of 5:1 means bartender mixed 20% spirit into original 50% spirit in the ratio of 5:1 Means 5/6 of the bottle is stoled by bartender which is 5/6*100 = 83.33% - 10 years agoHelpfull: Yes(4) No(2)
- 1 bottle is contained 50% of spirit , stolen by bartender and replaced having 20% spirit. Finally Bottle is contained 25% spirit.
Cheaper(c) quantity 20%
Dearer(d) Quantity 50%
Desire (m) Quantity 25%
d-m:m-c
25:5
5:1
bottle steal quantity 5/6
Percentage
5/6*100=83.33%
Ans 83.33% - 6 years agoHelpfull: Yes(3) No(0)
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