Two bodies A and B start from opposite ends P and Q of a straight road. They meet at a point 0.6D from P . Find the point of their fourth meeting.

• ans: 4.2
  because for meeting one time it required 0.6D
  for 2nd meeting it require 0.6+0.6+0.6=1.8
  for 3rd meeting it require 1.8+0.6+0.6=3
  for 4th meeting it require 3+0.6+0.6=4.2
  hence answer is 4.2
• 9 years agoHelpfull: Yes(2) No(0)
• Adding one point to Anusha..
  ans: 4.2 and 0.2D from P
  because for meeting one time it required 0.6D
  for 2nd meeting it require 0.6+0.6+0.6=1.8
  for 3rd meeting it require 1.8+0.6+0.6=3
  for 4th meeting it require 3+0.6+0.6=4.2
  hence answer is 4.2
  -----------
  Total 4.2 D i.e..
  Actual distance from P to Q is D.
  2 times P to Q and Q to P (total 4D) and 0.2D from P.
• 8 years agoHelpfull: Yes(1) No(0)
• Using formula for total distance travelled by a bodies when both of them are in opposite direction ->
  D + (n - 1)2D = 7D
  Where n is no. of trips.
  Since ratio of speed is 3 : 2 we should divide total distance in such ratio giving 4.2 and 2.8
• 8 years agoHelpfull: Yes(0) No(0)