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A,B,C are pipes attached to a cistren.A na d B can fill it in 20 and 30 ..while C empty it in 15 min..If A,B,C open successively for 1 min each.how soon the cistern will be filled?
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- 3 hours
3 minutes filling=(1/20)+(1/30)-(1/15)=1/60
So cistern will be filled in 3/(1/60)=180 minutes or 3 hours - 9 years agoHelpfull: Yes(1) No(1)
- Answer: 3hours or 180 minutes
Explanation :
A fills in 20 min
A will fill in one minute = 1/20th part
Similarly,
B will fill in one minute = 1/30th part
and c will empty tank in one minute = 1/15th part
son in first three minute part of tank filled = (1/20)+(1/30)-(1/15)
= 1/60 part
so 1/60 part in 3 minutes
total tank will be filled in (3*60) minutes
= 180 minute or 3 hours - 9 years agoHelpfull: Yes(1) No(0)
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