A man goes to a theatre to watch a movie along with his 4 family members and buy tickets. Ticket seller gives an offer “if you buy 6 ticket s, I will give extra 4 tickets” .that man bought 6 tickets along with extra 4 tickets. Then the ticket counter was closed .the man had 5 extra tickets .in theatre 10 persons were standing outside without getting ticket.
The wanted to give 5 tickets randomly to 5 persons for minimum cost(total tickets only for Rupees 15).in how many way
that tickets can be distributed to 5 persons with the cost of rupees 15(totl cost of 5 tickets).note:same amount should not
be repeated at a time and Rupees 0 should not be taken as amount

• To select 5 people from 10-10c5
  and there will be one case distribtion lie-6,4,3,2 and 1 rupees respectively.
  Now permution of these 5 notes-5!
  hence Required solution is-10c5*5!
  
• 9 years agoHelpfull: Yes(12) No(3)
• 10 people selection=10c5
  and condition is that no number shoould repeat and 0 should not be their and 5 tickt cost should be =15 so this can be formed bo only one way 1,2,3,4,5(rs)=1ways=1! and these can be distributed in 5! ways......... so 5!*1!=5! ans will be 5!*10c5
• 9 years agoHelpfull: Yes(10) No(0)
• 10c1 with ticket cost rupee 5 = 10
  9c1 with ticket cost rupee 4 = 9
  8c1 with ticket cost rupee 3 = 8
  7c1 with ticket cost rupee 2 = 7
  6c1 with ticket cost rupee 1 = 6
  addition 40
• 9 years agoHelpfull: Yes(6) No(0)
• 5 tickets at the cost of Rs 1 ,Rs 2, Rs 3, Rs 4, Rs 5 each respectively.
• 9 years agoHelpfull: Yes(3) No(4)
• To select 5 people 5c5.and to distribute 5!.total 5c5.5!
  
• 9 years agoHelpfull: Yes(2) No(6)
• Ans)10p5(10c5*5!)===>15 rupees divided int 1,2,3,4,5 rs.
  Now permutation====>with 10 men==10p5.
• 9 years agoHelpfull: Yes(2) No(0)
• can anyone explain briefly....
• 9 years agoHelpfull: Yes(1) No(0)
• did not understand the solution .. can anyone explain it
• 9 years agoHelpfull: Yes(1) No(0)