TCS
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Numerical Ability
Arithmetic
there is 16 question. 20 marks for attempting the paper. for each correct answer u get 5 marks and wrong answer you get 0 marks . if you dont attempt question you get 2 marks. which is not attainable marks.
a)97 b)96 c)95 d) all.
2)a series is given as
A 1 9
B 2 8 10
C 3 7 11
D 4 6 12
E 5 13
which char come at 2014th position.
Read Solution (Total 4)
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- 1. b) 96
I think there are 20 questions, in a paper.
97 is possible with 19 correct answers & 1 non attempt.
95 is possible with 19 correct answers & 1 wrong answer
So 96 is not attainable marks.
2) Character 'D' will come at 2014th position.
As first 5 positions are assigned to A,B,C,D & E respectively and from 6th position group of four number takes alternate positions as DCBA & BCDE, so finding 'n' groups of 4, we have 5+4n=2014 here n=502 with remainder 1, as 502th group of 4 will occupy B,C,D,E, so remainder 1 or next 2014th position will be occupied by 'D' - 9 years agoHelpfull: Yes(12) No(5)
- 1. there are 16 questions. taking option a i.e. 97, we get 20 marks for attempting+15*5 for correct answers +1*2 for not attempting = 97, so it is attainable. taking option c,i.e. 95, we get 20 marks for attempting+ 15*5 for correct answer + 1*0 for wrong answer= 95, so this is also attainable. but for option b, i.e. 96 we can't find any suitable order of arranging the correct answers or not attempting questions. so, option b is correct.
- 9 years agoHelpfull: Yes(10) No(0)
- pls some one explain the answer to 2nd question in details
- 9 years agoHelpfull: Yes(2) No(0)
- Hey, Can I know how this is solved ?
- 9 years agoHelpfull: Yes(0) No(0)
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