Two pyramids are thrown with faces 1,2,4,6. Find the probability to get a sum of even number on an their faces?
a) 5/8
b)3/4
(i dnt remember)

• 1 pyramid can show 4 different kind of arrangements
  
  1,2,4=7
  1,2,6=9
  1,4,6=11
  2,4,6=12
  
  So, out of 4 outcomes
  
  3 are odd and 1 is even.
  
  In question given two pyramids are thrown.
  So, to make some of their faces as even
  
  Condition 1: some of both individual faces of each pyramid is odd
  
  3/4 * 3/4
  =9/16
  
  Condition 2: some of both individual faces of pyramid is even
  1/4 + 1/4
  =1/16
  
  Total such conditions = 9/16 + 1/16
  = 10/16
  = 5/8
• 8 years agoHelpfull: Yes(17) No(0)
• total sum = 4*4=16
  favorable case odd+odd = even
  1*1=1;
  and
  even +even = even
  3*3=9
  so total = 10
  
  so probability = 10/16=5/8
  so b ans
• 8 years agoHelpfull: Yes(3) No(0)
• odd + odd =1/4*1/4
  even + even =3/4*3/4
  add both
  we get answer=5/8
• 8 years agoHelpfull: Yes(2) No(0)
• pyramids have 5 faces but in q.. given only 4 faces(1,2,4,6)
• 8 years agoHelpfull: Yes(2) No(0)
• Ans:a)5/8
  total favourable events=10
  total possible case=4*4=16
  P=10/16=5/8
• 8 years agoHelpfull: Yes(1) No(2)
• a-5/8 is d ri8 ans.
• 8 years agoHelpfull: Yes(0) No(0)
• its option b
• 8 years agoHelpfull: Yes(0) No(0)
• 5/8 is ryt answer
• 8 years agoHelpfull: Yes(0) No(0)
• i hav mrkd as 5/8 bt didnt get any mrks fr dt...
• 8 years agoHelpfull: Yes(0) No(0)
• @ Neha
  This question is asked on which date?
• 8 years agoHelpfull: Yes(0) No(0)
• askd on 12 nav 2015
• 8 years agoHelpfull: Yes(0) No(0)